What is the reason behind the functionality of shift() on one array versus the other, except for when it is universally applied on the latter

While examining the code below, I noticed that the compiler does not flag any issues with groups.shift(), but it does raise an error stating that depths.shift() is not a function. What could I be overlooking here? (I've already tried renaming depths and retyping it).

    const tag1x = (elem, content, groups = ['?','?','?'], depths = ['?','?'], optional = true, level = 0) => {
        let option = optional ? '?' : '';
        let template = `
            ${'\t'.repeat(level)}(${groups.shift()}:<$1[^>]*?DDD(${depths.shift()}:[0-9]+)[^>]*>)$3
            ${'\t'.repeat(level)}(${groups.shift()}:$2)
            ${'\t'.repeat(level)}(${groups.shift()}:</$1[^>]*?DDD(${depths.shift()}:[0-9]+)[^>]*>)$3
            `;
        return form(template, elem, content, option);
    }

However, a generic use of shift seems to resolve the issue:

    const tag1x = (elem, content, groups = ['?','?','?'], depths = ['?','?'], optional = true, level = 0) => {
        let option = optional ? '?' : '';
        let template = `
            ${'\t'.repeat(level)}(${groups.shift()}:<$1[^>]*?DDD(${[].shift.call(depths)}:[0-9]+)[^>]*>)$3
            ${'\t'.repeat(level)}(${groups.shift()}:$2)
            ${'\t'.repeat(level)}(${groups.shift()}:</$1[^>]*?DDD(${[].shift.call(depths)}:[0-9]+)[^>]*>)$3
            `;
        return form(template, elem, content, option);
    }

The updated code should now work correctly.

Answer №1

My initial interpretation of the situation was incorrect. The issue arose during runtime, most likely due to receiving a string input instead of an array input. In such cases, using

[].shift.call(myAccidentallyAString)
can resolve the problem as opposed to directly calling shift() on a string, which is not a valid function.

This scenario behaves similar to

Array.isArray(myStuff) ? myStuff.shift() : [myStuff].shift()
, indicating that perhaps myStuff is being converted to an object before the shift() method is applied.

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