What is the process for isolating variables from an array depending on their specific values?

Question

What is the process for isolating variables from an array depending on their specific values?

I have a collection of variables stored in an array. My goal now is to identify and extract the variables with the highest values, then store them in a separate array.

This task pertains to a JavaScript program that I am developing for my daughter's Wix website.

var kiara = 1;
var rodeo = 3;
var calypso = 3;
var balthazar = 3;
var mistral = 4;
var saya = 4;
var luna = 4;

var points = [{kiara}, {rodeo}, {calypso}, {balthazar}, {mistral}, {saya}, {luna}],

Since the variables are already arranged in ascending order based on their values, the program needs to identify ties at the top position (such as mistral, saya, and luna), extract these variables along with their respective values, and save them in a new array. In cases where only one variable has the highest value, that single variable will be stored in the new array.

javascript arrays variables

Answer 1

Answer №1

To extract the largest value from an array of objects, we can utilize a combination of .map and .reduce functions for efficient processing. By identifying the maximum value first, we can then isolate the objects in the points array that match this value based on their first properties, subsequently storing them in a separate array named newArray.

var maxValue = points
    .map(function(obj){ return obj[Object.keys(obj)[0]]; }) //extract numbers into an array
    .reduce(function(a, b){ return Math.max(a, b);}); //determine the maximum value

var newArray = points // filter objects with first property equal to maxValue
    .filter(function(obj){ return obj[Object.keys(obj)[0]] === maxValue; });

The output will display:

[{mistral: 4}, {saya: 4}, {luna: 4}]

Answer 2

To extract the largest value from an array of objects, we can utilize a combination of .map and .reduce functions for efficient processing. By identifying the maximum value first, we can then isolate the objects in the points array that match this value based on their first properties, subsequently storing them in a separate array named newArray.

var maxValue = points
    .map(function(obj){ return obj[Object.keys(obj)[0]]; }) //extract numbers into an array
    .reduce(function(a, b){ return Math.max(a, b);}); //determine the maximum value

var newArray = points // filter objects with first property equal to maxValue
    .filter(function(obj){ return obj[Object.keys(obj)[0]] === maxValue; });

The output will display:

[{mistral: 4}, {saya: 4}, {luna: 4}]

Answer 3

Answer №2

If your array is sorted, finding the maximum value is easy because it will be at the last position. You can simply retrieve this value and then filter out elements that match it:

var kiara = 1;
var rodeo = 3;
var calypso = 3;
var balthazar = 3;
var mistral = 4;
var saya = 4;
var luna = 4;

var points = [{kiara}, {rodeo}, {calypso}, {balthazar}, {mistral}, {saya}, {luna}];

// Since the array is ordered, the highest value is at the last position.
// Retrieve it like this:
let maxVal = Object.values(points[points.length - 1])[0];
console.log(maxVal);

// Now, filter the array to find elements matching the highest value
let highest = points.filter(x => Object.values(x)[0] === maxVal);
console.log(highest)

If your initial array is not sorted as mentioned, you can still find the highest value using a different approach:

var kiara = 1;
var rodeo = 3;
var calypso = 3;
var balthazar = 3;
var mistral = 4;
var saya = 4;
var luna = 4;

var points = [{saya}, {rodeo}, {mistral}, {balthazar}, {luna}, {kiara}, {calypso}];

// In case the array is not ordered, find the highest value.
// Obtain it like this:
let maxVal = points.reduce((max, v) => Math.max(Object.values(v)[0], max), null);
console.log(maxVal);

// Filter the array for elements matching the highest value
let highest = points.filter(x => Object.values(x)[0] === maxVal);
console.log(highest)

Answer 4

If your array is sorted, finding the maximum value is easy because it will be at the last position. You can simply retrieve this value and then filter out elements that match it:

var kiara = 1;
var rodeo = 3;
var calypso = 3;
var balthazar = 3;
var mistral = 4;
var saya = 4;
var luna = 4;

var points = [{kiara}, {rodeo}, {calypso}, {balthazar}, {mistral}, {saya}, {luna}];

// Since the array is ordered, the highest value is at the last position.
// Retrieve it like this:
let maxVal = Object.values(points[points.length - 1])[0];
console.log(maxVal);

// Now, filter the array to find elements matching the highest value
let highest = points.filter(x => Object.values(x)[0] === maxVal);
console.log(highest)

If your initial array is not sorted as mentioned, you can still find the highest value using a different approach:

var kiara = 1;
var rodeo = 3;
var calypso = 3;
var balthazar = 3;
var mistral = 4;
var saya = 4;
var luna = 4;

var points = [{saya}, {rodeo}, {mistral}, {balthazar}, {luna}, {kiara}, {calypso}];

// In case the array is not ordered, find the highest value.
// Obtain it like this:
let maxVal = points.reduce((max, v) => Math.max(Object.values(v)[0], max), null);
console.log(maxVal);

// Filter the array for elements matching the highest value
let highest = points.filter(x => Object.values(x)[0] === maxVal);
console.log(highest)

Answer 5

Answer №3

Check out this ES6 approach to solving the problem. It handles the scenario where the list is not in order, allowing the highest values to be situated anywhere within the list. Additionally, you can tweak the code to retrieve the smallest values if needed. Feel free to reach out with any queries about the code, and I'll provide assistance promptly.

const kiara = 1;
const rodeo = 3;
const calypso = 3;
const balthazar = 3;
const mistral = 4;
const saya = 4;
const luna = 4;


function getNamesWithHighestPoints(points) {
  const hash = {};

  for(let i = 0; i < points.length; i++) {

    let point = points[i];
    let name = Object.keys(point)[0];
    let score = Object.values(point)[0];

    if(hash[score] === undefined) {
      hash[score] = [point];
    }
    else {
      hash[score].push(point);
    }
  }

  let biggestScore = 0;
  Object.keys(hash).forEach(pointKey => {
    if(biggestScore < pointKey) {
      biggestScore = pointKey;
    }
  });
  return hash[biggestScore];
}
const points = [{kiara}, {rodeo}, {calypso}, {balthazar}, {mistral}, {saya}, {luna}];

console.log(getNamesWithHighestPoints(points));

Answer 6

Check out this ES6 approach to solving the problem. It handles the scenario where the list is not in order, allowing the highest values to be situated anywhere within the list. Additionally, you can tweak the code to retrieve the smallest values if needed. Feel free to reach out with any queries about the code, and I'll provide assistance promptly.

const kiara = 1;
const rodeo = 3;
const calypso = 3;
const balthazar = 3;
const mistral = 4;
const saya = 4;
const luna = 4;


function getNamesWithHighestPoints(points) {
  const hash = {};

  for(let i = 0; i < points.length; i++) {

    let point = points[i];
    let name = Object.keys(point)[0];
    let score = Object.values(point)[0];

    if(hash[score] === undefined) {
      hash[score] = [point];
    }
    else {
      hash[score].push(point);
    }
  }

  let biggestScore = 0;
  Object.keys(hash).forEach(pointKey => {
    if(biggestScore < pointKey) {
      biggestScore = pointKey;
    }
  });
  return hash[biggestScore];
}
const points = [{kiara}, {rodeo}, {calypso}, {balthazar}, {mistral}, {saya}, {luna}];

console.log(getNamesWithHighestPoints(points));

Answer 7

Answer №4

Here is a simple solution that can be accomplished with minimal code. When dealing with objects, utilizing for-in loops can simplify your workflow.

var kiara = 1;
var rodeo = 3;
var calypso = 3;
var balthazar = 3;
var mistral = 4;
var saya = 4;
var luna = 4;

var points = [{rodeo}, {calypso}, {balthazar}, {mistral}, {saya}, {luna},{kiara}];

var maxNumberArray = [];
var maxNamesArray = []; // New line added for storing names
var max;

for(var char in points){
    for(var name in points[char]){
        if(!max){
            max = points[char][name];
        } else {
            if(max < points[char][name]){
                max = points[char][name];
            }
        }
    }
}

for(var char in points){
    for(var name in points[char]){
        if(points[char][name] === max){
            maxNumberArray.push(points[char]);
            maxNamesArray.push(name); // Additional line to store names
        }
    }
}

console.log(JSON.stringify(maxNumberArray));
console.log(maxNamesArray); // Displaying names of maximum elements as well

:)

Answer 8

Here is a simple solution that can be accomplished with minimal code. When dealing with objects, utilizing for-in loops can simplify your workflow.

var kiara = 1;
var rodeo = 3;
var calypso = 3;
var balthazar = 3;
var mistral = 4;
var saya = 4;
var luna = 4;

var points = [{rodeo}, {calypso}, {balthazar}, {mistral}, {saya}, {luna},{kiara}];

var maxNumberArray = [];
var maxNamesArray = []; // New line added for storing names
var max;

for(var char in points){
    for(var name in points[char]){
        if(!max){
            max = points[char][name];
        } else {
            if(max < points[char][name]){
                max = points[char][name];
            }
        }
    }
}

for(var char in points){
    for(var name in points[char]){
        if(points[char][name] === max){
            maxNumberArray.push(points[char]);
            maxNamesArray.push(name); // Additional line to store names
        }
    }
}

console.log(JSON.stringify(maxNumberArray));
console.log(maxNamesArray); // Displaying names of maximum elements as well

:)

What is the process for isolating variables from an array depending on their specific values?

Answer №1

Answer №2

Answer №3

Answer №4

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