If I want to use JavaScript RegExp to match an expression string, how can I do it effectively?
For example:
'1**2*3+4' ->
['1', '**', '2', '*', '3', '+', '4']['1', '*', '*', '2', '*', '3', '+', '4']Is there a way to achieve this using the following RegExp pattern?
'1**2*3+4'.match(/[*\/+-]|\d+/g)
Additionally, is it possible to group (\*\*) together with +-*/ in brackets without making them stand out individually like:
/\*\*|[*\/+-]|\d+/g
To match one or more asterisks separately from the character class, you can use the following regex pattern: \*+. This will allow you to find instances of * without mixing with other characters like /, +, and -.
[\/+-]|\*+|\d+
[\/+-] - Matches either /, +, or -| - Or\*+ - Match one or more occurences of *| - Or\d+ - Match one or more digitslet s = '1**2*3+4';
console.log(s.match(/[\/+-]|\*+|\d+/g));If you want to also include matching +- as a single entity, you can repeat the character class by itself in the regex pattern.
[*\/+-]+|\d+
To capture a double-character inside the square brackets (as they are shorthand for single character OR), you must modify the regex pattern accordingly. Here is an example of how to achieve this:
/\*\*|[*\/+-]|\d+/g
The reason why this pattern captures ** is because \*\* appears before the single * in the bracket sequence.
Alternatively, if you wish to match any repeating special characters as individual groups (e.g., // should be matched as // instead of /,/), you need to expand the bracket options into separate | patterns and include + (indicating one or more occurrences of the preceding character) after each:
/\*+|\/+|\++|\-+|\d+/g
This expression instructs the regex engine to "match all instances of at least one *, at least one /, at least one +, at least one -, or at least one digit."
If you want to limit the matching to up to 2 occurrences of each character, you can substitute each + with {1,2}.
Implement a personalized quantifier:
'1**2*3+4'.match(/[*\/+-]{1,2}|\d+/g)
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