Validate the historical and present contents of a variable

Let's take a look at my code snippet:

<button id="submit">Roll</button>

<script>
    
function generateRandomNumber(range) {
   var result           = '';
   var characters       = '123456789';
   var charactersLength = characters.length;
   for ( var i = 0; i < range; i++ ) {
      result += characters.charAt(Math.floor(Math.random() * charactersLength));
   }
   return result;
}


var previousNumber = 0;

$('#submit').click(function(){
    
    var isWinner = false;
    
    var currentNumber = generateRandomNumber(3);
    
    if(currentNumber > previousNumber){
        isWinner = true;
    }
    
    previousNumber = currentNumber;
    
    alert(isWinner);
})

</script>

The issue I'm encountering is that the winner for each round is always true, as the variable previousNumber remains at 0. I actually intend to compare the highest and lowest numbers across rounds.

Answer №1

If you find that your code resets every time you run it with nodejs, consider starting by setting oldNumber to a random number.


<button id="submit">Roll</button>

<script>
    
function generateRandomNumber(length) {
   var result           = '';
   var characters       = '123456789';
   var charactersLength = characters.length;
   for ( var i = 0; i < length; i++ ) {
      result += characters.charAt(Math.floor(Math.random() * charactersLength));
   }
   return result;
}

var oldNumber = generateRandomNumber(3);

$('#submit').click(function(){
    
    var winner = false;
    
    var currentNumber = generateRandomNumber(3);
    
    if(currentNumber > oldNumber){
        winner = true;
    }
    
    oldNumber = currentNumber;
    
    alert(winner);
})

</script>

Answer №2

When using your randomNumber() function, it consistently returns a numeric string, which you then assign to the currentNumber variable. The issue arises when you try to compare this string with the oldNumber variable, which is actually a number. The problem lies in this comparison, as well as in the implementation of the randomNumber() function. It is important to compare two values of the same type, not two different types of numbers.

 if(currentNumber > oldNumber){
      winner = true;
 }

In the code snippet above, the comparison between a numeric string (currentNumber) and an actual number (oldNumber) results in a textual comparison of both operands in JavaScript. Since randomNumber() always returns a numeric string that is greater than "0" and never starts with "0", such as currentNumber="123" compared to oldNumber=0, JavaScript converts the number to a numeric string for comparison. As a result, because '1' comes after '0' in the textual comparison, the result will always be true. To resolve this issue, ensure that randomNumber() consistently returns a value of number type, instead of a numeric string. For further information, you can refer to this discussion. Make the necessary adjustments to the randomNumber() implementation to ensure it always returns a number type value.

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