Utilizing NodeSize to Optimize the Spacing Among Nodes in the D3 Tree Arr

Currently, I am trying to adjust the positioning of my rectangle nodes because they are overlapping, as illustrated in the image below:

In my research, I discovered that D3 provides a nodeSize and separation method. However, I encountered difficulties implementing these methods effectively.

I came across a blog post addressing this issue, where the author mentions:

The size property doesn’t exist in nodes, so it will be whatever property you want to control the size of them.

This statement contradicts the existence of the nodeSize method in D3. Therefore, I suspect that either I am using the method incorrectly or the blog post is outdated. My goal is to configure my nodes to match the dimensions of the rectangles and evenly space them out to prevent overlaps. Can anyone provide guidance on the correct utilization of these methods? The documentation regarding these techniques lacks clarity and has not been informative thus far. Additionally, I have struggled to find examples demonstrating alterations to the nodeSize in tree structures or the necessity for separation with rectangular objects (while circular examples can be found, I believe they are too dissimilar...)

Below is the relevant code snippet. I will attempt to set up a JSFiddle for reference.

var margin = {top: 20, right: 120, bottom: 20, left: 120},
    height = 960 - margin.right - margin.left,
    width = 800 - margin.top - margin.bottom,
    rectW = 70;
    rectH = 30;
    //bbox = NaN,
    maxTextLength = 0;

var i = 0,
    duration = 750,
    root;


//paths from each node drawn initially here
//changed to d.x, d.y
var diagonal = d3.svg.diagonal()
    .projection(function(d) { return [d.x+rectW/2, d.y+rectH/2];
    //.projection(function(d) { return [d.x+bbox.getBBox().width/2, d.y+bbox.getBBox().height/2]; 
});

var tree = d3.layout.tree()
    .nodeSize([30,70])
    .separation(function(a, b) { return (a.parent == b.parent ? 1 : 2); })
    .size([width, height]);

var svg = d3.select("body")
            .append("svg")
              .attr("height","100%").attr("width","100%")
              .call(d3.behavior.zoom().on("zoom", redraw))
              .append("g")
                .attr("transform", "translate(" + margin.top + "," + margin.left + ")");

Answer №1

UPDATE 05/04/2018: There have been significant changes in d3, making it more modular and improved. This answer pertains to an older version of d3 (v3).

Although many findings are still applicable to the d3-hierarchy package under cluster.size() and cluster.nodeSize(), I am considering updating my example using that newer functionality. For historical reference, I will leave the existing content as is.


Take a look at this jsFiddle: http://jsfiddle.net/augburto/YMa2y/

EDIT: The example has been updated and moved to Codepen for better editing capabilities. The jsFiddle link remains active, but Codepen offers a more user-friendly interface for forking projects. I plan to include the example directly in this answer after condensing the content.

http://codepen.io/augbog/pen/LEXZKK

As I revisit this response, I discussed with a colleague and examined the source code for size and nodeSize.

  tree.size = function(x) {
    if (!arguments.length) return nodeSize ? null : size;
    nodeSize = (size = x) == null;
    return tree;
  };

  tree.nodeSize = function(x) {
    if (!arguments.length) return nodeSize ? size : null;
    nodeSize = (size = x) != null;
    return tree;
  };

Setting a size establishes fixed dimensions for the tree, while nodeSize allows for dynamic resizing. Mixing up these declarations can lead to unintended consequences!

Key point: If utilizing nodeSize, avoid defining a fixed size. Otherwise, the size will default to null.

EDIT: The documentation from D3.js has been updated, offering improved clarity. Much appreciated to whoever made those updates!

The nodeSize property overrides tree.size; specifying tree.nodeSize sets tree.size to null.

This is how my tree appears now. Additionally, zoom functionality and text centering within rectangles have been incorporated.

Answer №2

After conducting some additional research, I finally grasped the accepted answer and wanted to share my findings...

To prevent node overlapping when using .size(), switch to .nodeSize()

The use of .size() in setting a tree's size can result in nodes overlapping due to varying spacing. However, by utilizing .nodeSize(), each node is allocated specific space to ensure no overlap occurs.

The following code proved successful for me:

var nodeWidth = 300;
var nodeHeight = 75;
var horizontalSeparationBetweenNodes = 16;
var verticalSeparationBetweenNodes = 128;

var tree = d3.layout.tree()
    .nodeSize([nodeWidth + horizontalSeparationBetweenNodes, nodeHeight + verticalSeparationBetweenNodes])
    .separation(function(a, b) {
        return a.parent == b.parent ? 1 : 1.25;
    });

By including horizontalSeparationBetweenNodes and verticalSeparationBetweenNodes, node edges stopped touching. Additionally, implementing the .separation() function helped reduce wasted space between cousin nodes due to their wide size.

Please note: This solution pertains to d3 v3, not v4

Answer №3

Big thank you to everyone who has shared their insights here, invaluable information. For those struggling with the offset issue that often arises with a horizontally arranged tree, I wanted to offer some advice.

The key point to remember is that when transitioning from using .size() to .nodeSize() on a horizontal tree, the root node may appear to shift or reorient itself to (0,0). According to the d3.js documentation, this adjustment is intentional (https://github.com/d3/d3-hierarchy/blob/master/README.md#tree_nodeSize)

However, you can easily correct this by ensuring to reposition your viewBox. In other words, when you .append your svg, be sure to explicitly define your viewBox. Here's a simple solution that worked for me...

svg = d3.select("#tree").append("svg")
            .attr("width", width + margin.right + margin.left)
            .attr("height", height + 0 + 0)
            .attr("viewBox", "0 "+(-1*(height-margin.top-margin.bottom)/2)+" "+width+" "+height)
            .append("g")
            .attr("transform", "translate("
                  + margin.left + "," + 0 + ")");

Answer №4

For those working with react-d3-tree who wish to incorporate spacing between nodes, consider implementing the following code snippet:

<Tree
                nodeSize={{ x: 250, y: 200 }}
                ...
/>

Feel free to customize the values according to your specific needs :)

Answer №5

Now, D3 is utilizing Observable for its operations.

If you want to specify the nodeSize, locate this specific line of code:

main.variable(observer("tree")).define("tree", ["d3","dx","dy"],
function(d3,dx,dy){return(
d3.tree()

You can then adjust nodeSize by adding constants:

main.variable(observer("tree")).define("tree", ["d3","dx","dy"],
function(d3,dx,dy){return(
d3.tree().nodeSize([dx + 10, dy + 10])

Alternatively, you can employ a function to customize values based on chart dimensions, following a similar approach discussed in another answer using the older version of D3.

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