Utilize linqjs to filter an array based on the values present in another array

Question

Utilize linqjs to filter an array based on the values present in another array

We have two arrays to work with here. The first array consists of objects:

let objectArray = [{
    FullName: "Person1",
    PersonId: "id1"
  },
  {
    FullName: "Person2",
    PersonId: "id2"
  },
  {
    FullName: "Person3",
    PersonId: "id3"
  },
  {
    FullName: "Person4",
    PersonId: "id4"
  }
];

The second array contains strings which are some ids:

let idsArray= ["id1", "id2", "id3"];

The task at hand is to remove the objects from the first array that have ids present in the second array.

The expected result after deletion is as follows:

firstArray = [{
  FullName: "Person4",
  PersonId: "id4"
}];

While exploring documentation on Linqjs, I came across the Except() method, which aids in eliminating elements from one array based on another.

To utilize this method effectively, a new array needs to be created from objectArray only containing elements whose ids match those in idsArray.

For example:

let filteredArray = Enumerable.From(objectArray).Except(theNewArray).ToArray();

The creation of this new array can be achieved by using the Where() method provided by Linqjs.

The major challenge I face now is figuring out how to generate this new array while considering we have an array of ids for filtering purposes.

javascript arrays linq.js

Answer 1

Answer №1

You have the option to utilize Vanilla JavaScript's array.filter and array.includes in the following manner:

let objectArray = [
  {FullName: "Person1", PersonId: "id1"},
  {FullName: "Person2", PersonId: "id2"},
  {FullName: "Person3", PersonId: "id3"},
  {FullName: "Person4", PersonId: "id4"}
];
    
  let excludeIdsArray= ["id1", "id2", "id3"];
  
  let newObj = objectArray.filter(obj => !excludeIdsArray.includes(obj.PersonId))
  
  console.log(newObj)

Alternatively, you can make use of array.reduce and array.includes like so:

let objectArray = [
  {FullName: "Person1", PersonId: "id1"},
  {FullName: "Person2", PersonId: "id2"},
  {FullName: "Person3", PersonId: "id3"},
  {FullName: "Person4", PersonId: "id4"}
];
        
let excludeIdsArray= ["id1", "id2", "id3"];

let newObj = objectArray.reduce((arr, myObject) => {
  if(!excludeIdsArray.includes(myObject.PersonId)) {
    arr.push(myObject)
  } 
  return arr
}, [])
  

console.log(newObj)

Answer 2

You have the option to utilize Vanilla JavaScript's array.filter and array.includes in the following manner:

let objectArray = [
  {FullName: "Person1", PersonId: "id1"},
  {FullName: "Person2", PersonId: "id2"},
  {FullName: "Person3", PersonId: "id3"},
  {FullName: "Person4", PersonId: "id4"}
];
    
  let excludeIdsArray= ["id1", "id2", "id3"];
  
  let newObj = objectArray.filter(obj => !excludeIdsArray.includes(obj.PersonId))
  
  console.log(newObj)

Alternatively, you can make use of array.reduce and array.includes like so:

let objectArray = [
  {FullName: "Person1", PersonId: "id1"},
  {FullName: "Person2", PersonId: "id2"},
  {FullName: "Person3", PersonId: "id3"},
  {FullName: "Person4", PersonId: "id4"}
];
        
let excludeIdsArray= ["id1", "id2", "id3"];

let newObj = objectArray.reduce((arr, myObject) => {
  if(!excludeIdsArray.includes(myObject.PersonId)) {
    arr.push(myObject)
  } 
  return arr
}, [])
  

console.log(newObj)

Answer 3

Answer №2

To efficiently filter an array, you can utilize the filter() method. Create a set object using new Set() to easily check for the existence of the PersonId. This eliminates the need to iterate through each element with filter().

let objectArray = [
  {FullName: "Person1", PersonId: "id1"},
  {FullName: "Person2", PersonId: "id2"},
  {FullName: "Person3", PersonId: "id3"},
  {FullName: "Person4", PersonId: "id4"}
];

let idsArray = ["id1", "id2", "id3"];

let idsToRemove = new Set(idsArray);
let result = objectArray.filter(o => !idsToRemove.has(o.PersonId));

console.log(result);

An alternative approach is to use includes() to determine if a specific string is present in an array.

let objectArray = [
  {FullName: "Person1", PersonId: "id1"},
  {FullName: "Person2", PersonId: "id2"},
  {FullName: "Person3", PersonId: "id3"},
  {FullName: "Person4", PersonId: "id4"}
];

let idsArray = ["id1", "id2", "id3"];

let result = objectArray.filter(o => !idsArray.includes(o.PersonId));

console.log(result);

Note: To update the existing variable without creating a new one, you can directly reassign it like so:

objectArray = objectArray.filter(o => ...);

Answer 4

To efficiently filter an array, you can utilize the filter() method. Create a set object using new Set() to easily check for the existence of the PersonId. This eliminates the need to iterate through each element with filter().

let objectArray = [
  {FullName: "Person1", PersonId: "id1"},
  {FullName: "Person2", PersonId: "id2"},
  {FullName: "Person3", PersonId: "id3"},
  {FullName: "Person4", PersonId: "id4"}
];

let idsArray = ["id1", "id2", "id3"];

let idsToRemove = new Set(idsArray);
let result = objectArray.filter(o => !idsToRemove.has(o.PersonId));

console.log(result);

An alternative approach is to use includes() to determine if a specific string is present in an array.

let objectArray = [
  {FullName: "Person1", PersonId: "id1"},
  {FullName: "Person2", PersonId: "id2"},
  {FullName: "Person3", PersonId: "id3"},
  {FullName: "Person4", PersonId: "id4"}
];

let idsArray = ["id1", "id2", "id3"];

let result = objectArray.filter(o => !idsArray.includes(o.PersonId));

console.log(result);

Note: To update the existing variable without creating a new one, you can directly reassign it like so:

objectArray = objectArray.filter(o => ...);

Answer 5

Answer №3

If you want to filter out specific items from an array based on certain criteria, you can leverage the Array.prototype.filter method along with indexOf. This allows you to check if a property like PersonId is present in an array of IDs that you want to exclude. If it's not found, you can then add it to a new array called filteredArray. Below is a code snippet demonstrating this:

let objects = [{
    FullName: "Person1",
    PersonId: "id1"
  },
  {
    FullName: "Person2",
    PersonId: "id2"
  },
  {
    FullName: "Person3",
    PersonId: "id3"
  },
  {
    FullName: "Person4",
    PersonId: "id4"
  }
];

let toDelete = ["id1", "id2", "id3"];

// Use Array.prototype.filter method to eliminate unwanted elements
var filteredObjects = objects.filter(function(element) {
  return toDelete.indexOf(element.PersonId) === -1;
});

console.log(filteredObjects);

This approach utilizes pure JavaScript without relying on external libraries like linqjs. Consider removing unnecessary dependencies from your project for better maintenance.

Answer 6

If you want to filter out specific items from an array based on certain criteria, you can leverage the Array.prototype.filter method along with indexOf. This allows you to check if a property like PersonId is present in an array of IDs that you want to exclude. If it's not found, you can then add it to a new array called filteredArray. Below is a code snippet demonstrating this:

let objects = [{
    FullName: "Person1",
    PersonId: "id1"
  },
  {
    FullName: "Person2",
    PersonId: "id2"
  },
  {
    FullName: "Person3",
    PersonId: "id3"
  },
  {
    FullName: "Person4",
    PersonId: "id4"
  }
];

let toDelete = ["id1", "id2", "id3"];

// Use Array.prototype.filter method to eliminate unwanted elements
var filteredObjects = objects.filter(function(element) {
  return toDelete.indexOf(element.PersonId) === -1;
});

console.log(filteredObjects);

This approach utilizes pure JavaScript without relying on external libraries like linqjs. Consider removing unnecessary dependencies from your project for better maintenance.

Answer 7

Answer №4

To remove unwanted PersonId, one can utilize the Except function from linq.js. By providing an array of objects and a column parameter, excluding specific IDs becomes straightforward.

var objectArray = [{ FullName: "Person1", PersonId: "id1" }, { FullName: "Person2", PersonId: "id2" }, { FullName: "Person3", PersonId: "id3" }, { FullName: "Person4", PersonId: "id4" }],
idsArray = ["id1", "id2", "id3"],
result = Enumerable
.From(objectArray)
.Except(
Enumerable.From(idsArray).Select("{ PersonId: $ }"),
"$.PersonId"
)
.ToArray();

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

<script src="https://cdnjs.cloudflare.com/ajax/libs/linq.js/2.2.0.2/linq.js"></script>

Answer 8

To remove unwanted PersonId, one can utilize the Except function from linq.js. By providing an array of objects and a column parameter, excluding specific IDs becomes straightforward.

var objectArray = [{ FullName: "Person1", PersonId: "id1" }, { FullName: "Person2", PersonId: "id2" }, { FullName: "Person3", PersonId: "id3" }, { FullName: "Person4", PersonId: "id4" }],
idsArray = ["id1", "id2", "id3"],
result = Enumerable
.From(objectArray)
.Except(
Enumerable.From(idsArray).Select("{ PersonId: $ }"),
"$.PersonId"
)
.ToArray();

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

<script src="https://cdnjs.cloudflare.com/ajax/libs/linq.js/2.2.0.2/linq.js"></script>

Utilize linqjs to filter an array based on the values present in another array

Answer №1

Answer №2

Answer №3

Answer №4

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