Using Regex with JavaScript while ignoring letter case

I am trying to extract a query string from my URL using JavaScript, and I need to perform a case-insensitive comparison for the query string name. In order to achieve this, here is the code snippet that I am currently using:

var results = new RegExp('[\\?&]' + name + '=([^&#]*)').exec(window.location.href);
if (!results) { return 0; }
return results[1] || 0;

However, the code above performs a case-sensitive search. I attempted using /<regex>/i but it did not provide the desired outcome. Do you have any suggestions on how I can accomplish a case-insensitive search?

Answer №1

One way to handle case sensitivity is by using the 'i' modifier in regular expressions

var results = new RegExp('[\\?&]' + name + '=([^&#]*)', 'i').exec(window.location.href);

Answer №2

The second argument provides the modifiers:

new RegExp('[\\?&]' + attribute + '=([^&#]*)', "i")

Answer №3

This code snippet demonstrates a quick and efficient way to replace vowels with 'X' in a given string.

const replaceVowels = (str) => {
  return str.replace(/[aeiou]/gi, 'X');
}

console.log(replaceVowels('Hello world!')); //"HXllX wXRld!"

Answer №4

For instance, when searching for the word date, whether in upper or lowercase, you must utilize the parameter i

The "i" value translates to case insensitivity

Here is an example:

const text = "some content with dAtE";
/date/i.test(text)

Alternatively, use this pattern:

const text = "some content with dAtE";
 new RegExp("/date/","i");

Answer №5

Here's another approach to consider: instead of resorting to "case insensitive regex", you can achieve the same result by simply adjusting the case of the strings being compared:

text1 = 'Good Morning!';
text2 = 'good morning!';
result = text1.lower() == text2.lower();

This method may be easier for others to understand and interpret the original intention!

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