Looking to refactor this code snippet:
this.serverlist = data.NodeList.reduce((accumulator, currentValue) => {
if (currentValue.productTypeId === "1") {
accumulator.push(currentValue.HostName);
}
return accumulator;
}, []);
Is there a way for me to replace the .map and .filter functions with just .reduce? If so, how can I achieve that?
Is there a way to replace the
.mapand.filterstatements with.reduce? How can I achieve that?
It is not recommended to do so.
The purpose of the .reduce function is to condense the entire collection into a new single value (or object), typically used for aggregating values (e.g. SUM, Count) or filling a Set<T> which does not align with your current task.
Instead, continue chaining the map and filter methods together (start with filter to avoid encountering undefined).
Here's an example:
this.serverList = data.NodeList
.filter( item => item.productTypeId === '1' && typeof item.HostName === 'string' )
.map( item => item.hostName )
.sort();
Keep in mind that while .filter and .map produce new Array objects, the .sort() method does not.
I interpreted your code snippet as follows:
const NodeList = [
{ productTypeId: "1", HostName: "abc.com" },
{ productTypeId: "2", HostName: "abc.com" },
{ productTypeId: "1" },
{ productTypeId: "1", HostName: "xyz.com" },
]
let serverlist = NodeList.map(a => {
if (a.productTypeId === "1") {
return a.HostName
}
})
serverlist = serverlist.filter(x => {
return x !== undefined
})
console.log(serverlist)
// [ 'abc.com', 'xyz.com' ]You can simplify this logic by using reduce, combining filter and extracting relevant data efficiently in one go:
const NodeList = [
{ productTypeId: "1", HostName: "abc.com" },
{ productTypeId: "2", HostName: "abc.com" },
{ productTypeId: "1" },
{ productTypeId: "1", HostName: "xyz.com" },
]
const serverlist = NodeList.reduce((acc, el) => {
if (el.productTypeId === "1" && el.HostName) {
acc.push(el.HostName)
}
return acc
}, [])
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