Given an array arr[8,4,2,1,7,5,3,0] containing 8 elements, I am looking for a way to randomly select each number from the array without any repeats. The goal is to ensure that every number is picked exactly once.
Given an array arr[8,4,2,1,7,5,3,0] containing 8 elements, I am looking for a way to randomly select each number from the array without any repeats. The goal is to ensure that every number is picked exactly once.
This code can be simplified by using a basic while loop:
const numbers=[8,4,2,1,7,5,3,0];
while(numbers.length>0) {
let index = Math.floor(Math.random() * Math.floor(numbers.length));
console.log(`Selected number: ${numbers[index]}`);
numbers.splice(index,1);
};
Example output:
// "Selected number: 4"
// "Selected number: 7"
// "Selected number: 0"
// "Selected number: 2"
// "Selected number: 1"
// "Selected number: 3"
// "Selected number: 8"
// "Selected number: 5"
Codepen: http://jsbin.com/bukoqujupo/edit?js,console
This code snippet essentially loops through the array, randomly selecting and displaying elements until all are picked. It repeats this process as long as there are elements in the array.
Here is a potential solution...
let numArray = [8,4,2,1,7,5,3,0];
let shuffleArray = (arr) => {
for(var j, x, i = arr.length; i; j = parseInt(Math.random() * i), x = arr[--i], arr[i] = arr[j], arr[j] = x);
return arr;
};
console.log(shuffleArray(numArray))Is this what you had in mind?
function generateRandomNumber(max) {
return Math.floor(Math.random() * Math.floor(max));
}
let numbers = [8, 4, 2, 1, 7, 5, 3, 0],
selectedNumbers = [];
function pickRandomNumber() {
let randomIndex = Math.floor(Math.random() * Math.floor(numbers.length));
if (selectedNumbers.indexOf(randomIndex) !== -1) {
return pickRandomNumber()
}
selectedNumbers.push(randomIndex);
return numbers[randomIndex]
}
numbers.forEach(() => {
console.log(pickRandomNumber());
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