Find a way to sift through an array of objects to ensure that each object is distinct from the others

Here is an array where objects with the same values for st and ct should be considered identical. For example, the first and third objects have the same values for st and ct, so the third object should be filtered out of the final array. How can I achieve this filtering using the array.filter method? I have reviewed the documentation but I am unsure how to define the conditional for the filter function.

[{
  "st": "2012",
  "id": "43",
  "ct": "1",
  "sd": "2"
},
{
  "st": "2015",
  "id": "45",
  "ct": "2",
  "sd": "2"
},
{
  "st":"2015",
  "id": "45",
  "ct": "2",
  "sd": "1"
},]

Answer №1

Here is a solution for you:

const findDuplicates = (arr) => {
  let uniqueArray = arr.filter((element, index, self) => {
    return self.findIndex(e => e.ct === element.ct && e.st === element.st) !== index;
  });
  return uniqueArray;
}

Answer №2

var items = [{
      "year":"2012",
      "id": "43",
      "category": "1",
      "status": "2"
    },
    {
      "year":"2015",
      "id": "453",
      "category": "2",
      "status": "2"
    },
    {
        "year":"2012", // this record is a duplicate
        "category":"1"
    }
];

// Utilizing a Set to maintain uniqueness eliminates the need for looping through the entire array using methods like .findIndex()
var knownKeys = new Set();

var uniqueItems = items.filter(function(item) {
    key = item.year + item.category;
    return !knownKeys.has(key) && knownKeys.add(key);
});

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