DESCRIPTION: A collection of elements is classified as zero-plentifull if it contains multiple occurrences of zeros, and each sequence of zeros consists of at least 4 items.
The objective is to determine the number of zero sequences in the array if it meets the criteria of being zero-plentifull, if not, return 0.
Examples: [0, 0, 0, 0, 0, 1] --> 1
1 group of 5 zeros (>= 4), so the outcome is 1
[0, 0, 0, 0, 1, 0, 0, 0, 0] --> 2
2 groups of 4 zeros (>= 4), thus the output is 2
[0, 0, 0, 0, 1, 0] --> 0 1 group of 4 zeros and 1 group of 1 zero (< 4) every sequence of zeros must be at least 4 in length, so the result is 0
[0, 0, 0, 1, 0, 0] --> 0 1 group of 3 zeros (< 4) and 1 group of 2 zeros (< 4)
[1, 2, 3, 4, 5] --> 0 no zeros
[] --> 0 no zeros
function zeroPlentiful(arr) {
let counter = [];
let index = 0;
arr.forEach((num, idx) => {
if (num === 0) {
counter[index] = counter[index] ? counter[index] + 1 : 1;
} else {
index = counter.length;
}
});
return counter.every(item => item >= 4) ? counter.length : 0;
}
Could someone kindly provide a step-by-step explanation of what the code is doing? I've tried solving this problem multiple times and reviewed various solutions, but I'm still struggling to comprehend the exact process. I know that the forEach loop is checking for zeros and non-zero numbers, but I need clarity on the overall functionality.