Create a duplicate of the information stored within the $scope variable

Question

Create a duplicate of the information stored within the $scope variable

Suppose there are multiple variables stored in a $scope and the objective is to create a new object that only includes those variables, excluding all the internal Angular-related data. The specific names of the $scope variables may not be known.

This can be achieved through:

$scope.a = "Test";
$scope.b = {x: 1, y: 2};
$scope.c = 99;
//potentially other unidentified variables

var obj = angular.copy_without_angular_stuff($scope);

What approach should be used to extract only the pertinent data?

javascript angularjs

Answer 1

Answer №1

A different approach you can take is to utilize

this

in place of

$scope

Check out the Plnkr example here

Controller:

angular.module('myApp').controller('MyCtrl', function(){
  var vm = this;

  vm.a = 'test';

  vm.b = {a: 'a', b: 'b'};

  vm.c = 123;

  var obj = vm;

});

In the view, I have displayed each value attached to VM along with VM itself which shows only a, b, and c as its attached objects.

vm.a: {{vm.a}}
<br/>
vm.b: {{vm.b}}
<br/>
vm.c: {{vm.c}}
<br/>

vm: {{vm}}

UPDATE

If you are not able to choose between $scope or not, you can refer to the updated plnkr example using $scope.

Controller:

angular.module('myApp').controller('My2ndCtrl', function($scope) {
  $scope.a = 'test';

  $scope.b = {a: 'a', b: 'b'};

  $scope.c = 123;

  var obj = {};


  for(var k in $scope) {
    if($scope.hasOwnProperty(k) && k.indexOf('$') < 0) {
      obj[k] = $scope[k]
    }
  }
 console.log(obj);
});

The resulting object is:

{a: "test", b: Object, c: 123}

Answer 2

A different approach you can take is to utilize

this

in place of

$scope

Check out the Plnkr example here

Controller:

angular.module('myApp').controller('MyCtrl', function(){
  var vm = this;

  vm.a = 'test';

  vm.b = {a: 'a', b: 'b'};

  vm.c = 123;

  var obj = vm;

});

In the view, I have displayed each value attached to VM along with VM itself which shows only a, b, and c as its attached objects.

vm.a: {{vm.a}}
<br/>
vm.b: {{vm.b}}
<br/>
vm.c: {{vm.c}}
<br/>

vm: {{vm}}

UPDATE

If you are not able to choose between $scope or not, you can refer to the updated plnkr example using $scope.

Controller:

angular.module('myApp').controller('My2ndCtrl', function($scope) {
  $scope.a = 'test';

  $scope.b = {a: 'a', b: 'b'};

  $scope.c = 123;

  var obj = {};


  for(var k in $scope) {
    if($scope.hasOwnProperty(k) && k.indexOf('$') < 0) {
      obj[k] = $scope[k]
    }
  }
 console.log(obj);
});

The resulting object is:

{a: "test", b: Object, c: 123}

Answer 3

Answer №2

It's rather surprising that I am suggesting this, but it may be worth considering refactoring your code to eliminate the need for such a workaround. Even if you find yourself in a situation where this is necessary...

$scope.test = 4;
var copiedObject = {};
for(var key in $scope){
    if(key[0] != '$' && key != 'this'){
        copiedObject[key] = $scope[key];
    }
}
console.log(copiedObject);

This snippet will iterate through all keys and filter out the Angular-specific elements. You can view a working example on jsFiddle:

http://jsfiddle.net/n8bz4L7e/

Please note: If there are references within the object or other $scope variables stored for any reason, those will also be copied over. As mentioned by others, this could potentially be an XY problem.

Answer 4

It's rather surprising that I am suggesting this, but it may be worth considering refactoring your code to eliminate the need for such a workaround. Even if you find yourself in a situation where this is necessary...

$scope.test = 4;
var copiedObject = {};
for(var key in $scope){
    if(key[0] != '$' && key != 'this'){
        copiedObject[key] = $scope[key];
    }
}
console.log(copiedObject);

This snippet will iterate through all keys and filter out the Angular-specific elements. You can view a working example on jsFiddle:

http://jsfiddle.net/n8bz4L7e/

Please note: If there are references within the object or other $scope variables stored for any reason, those will also be copied over. As mentioned by others, this could potentially be an XY problem.

Answer 5

Answer №3

$scope object contains various interval properties that start with $. To work around this, you can selectively copy properties that do not begin with $, or create a map for the internal $scope properties and only copy those that are not in the map.
Please note: The list of internal properties may vary across different versions of Angular.

angular.module('app', [])
  .controller('ctrl1', function($scope) {
    function clearCopy(scope) {
      var dest = {};
      for (var i in scope) {
        if (scope.hasOwnProperty(i) && i[0] !== '$' && i !== 'this') {
          dest[i] = scope[i];
        }
      }
      return dest;
    }
    $scope.a = "Test";
    $scope.b = {
      x: 1,
      y: 2
    };
    $scope.c = 99;

    $scope.copy1 = clearCopy($scope);
  })
  .controller('ctrl2', function($scope) {
    function clearCopy(scope) {
      var internalProperiesMap = {
          $$ChildScope: true,
          $$childHead: true,
          $$childTail: true,
          $$listenerCount: true,
          $$listeners: true,
          $$nextSibling: true,
          $$prevSibling: true,
          $$watchers: true,
          $$watchersCount: true,
          $id: true,
          $parent: true
        },
        dest = {};
      for (var i in scope) {
        if (scope.hasOwnProperty(i) && !internalProperiesMap[i]) {
          dest[i] = scope[i];
        }
      }
      return dest;
    }
    $scope.a = "Test";
    $scope.b = {
      x: 1,
      y: 2
    };
    $scope.c = 99;
    $scope.copy2 = clearCopy($scope);
  }).controller('ctrl3', function($scope) {
    function clearCopy(scope) {
      var internalProperiesMap = {
        $$ChildScope: true,
        $$childHead: true,
        $$childTail: true,
        $$listenerCount: true,
        $$listeners: true,
        $$nextSibling: true,
        $$prevSibling: true,
        $$watchers: true,
        $$watchersCount: true,
        $id: true,
        $parent: true
      };
      return Object.keys(scope).reduce(function(acc, el) {
        if (el[0] !== '$' && typeof scope[el] !== "function") {
          acc[el] = scope[el];
        }
        return acc;
      }, {});
    }
    $scope.a = "Test";
    $scope.b = {
      x: 1,
      y: 2
    };
    $scope.c = 99;
    $scope.fun = function(d){return d;};

    $scope.copy3 = clearCopy($scope);
  console.log($scope.copy3);
  });

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.4.0/angular.js"></script>
<div ng-app='app'>
  <div ng-controller='ctrl1'>copy 1: {{copy1}}</div>
  <div ng-controller='ctrl2'>copy 2: {{copy2}}</div>
  <div ng-controller='ctrl3'>copy 3: {{copy3}}</div>
</div>

However, it appears to be a case of XY problem

Answer 6

$scope object contains various interval properties that start with $. To work around this, you can selectively copy properties that do not begin with $, or create a map for the internal $scope properties and only copy those that are not in the map.
Please note: The list of internal properties may vary across different versions of Angular.

angular.module('app', [])
  .controller('ctrl1', function($scope) {
    function clearCopy(scope) {
      var dest = {};
      for (var i in scope) {
        if (scope.hasOwnProperty(i) && i[0] !== '$' && i !== 'this') {
          dest[i] = scope[i];
        }
      }
      return dest;
    }
    $scope.a = "Test";
    $scope.b = {
      x: 1,
      y: 2
    };
    $scope.c = 99;

    $scope.copy1 = clearCopy($scope);
  })
  .controller('ctrl2', function($scope) {
    function clearCopy(scope) {
      var internalProperiesMap = {
          $$ChildScope: true,
          $$childHead: true,
          $$childTail: true,
          $$listenerCount: true,
          $$listeners: true,
          $$nextSibling: true,
          $$prevSibling: true,
          $$watchers: true,
          $$watchersCount: true,
          $id: true,
          $parent: true
        },
        dest = {};
      for (var i in scope) {
        if (scope.hasOwnProperty(i) && !internalProperiesMap[i]) {
          dest[i] = scope[i];
        }
      }
      return dest;
    }
    $scope.a = "Test";
    $scope.b = {
      x: 1,
      y: 2
    };
    $scope.c = 99;
    $scope.copy2 = clearCopy($scope);
  }).controller('ctrl3', function($scope) {
    function clearCopy(scope) {
      var internalProperiesMap = {
        $$ChildScope: true,
        $$childHead: true,
        $$childTail: true,
        $$listenerCount: true,
        $$listeners: true,
        $$nextSibling: true,
        $$prevSibling: true,
        $$watchers: true,
        $$watchersCount: true,
        $id: true,
        $parent: true
      };
      return Object.keys(scope).reduce(function(acc, el) {
        if (el[0] !== '$' && typeof scope[el] !== "function") {
          acc[el] = scope[el];
        }
        return acc;
      }, {});
    }
    $scope.a = "Test";
    $scope.b = {
      x: 1,
      y: 2
    };
    $scope.c = 99;
    $scope.fun = function(d){return d;};

    $scope.copy3 = clearCopy($scope);
  console.log($scope.copy3);
  });

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.4.0/angular.js"></script>
<div ng-app='app'>
  <div ng-controller='ctrl1'>copy 1: {{copy1}}</div>
  <div ng-controller='ctrl2'>copy 2: {{copy2}}</div>
  <div ng-controller='ctrl3'>copy 3: {{copy3}}</div>
</div>

However, it appears to be a case of XY problem

Answer 7

Answer №4

One approach that might work is to transfer the attributes of a specific element, such as $scope, to a different element:

for(var k in $scope) {
  newElement[k] = $scope[k];
}

Answer 8

One approach that might work is to transfer the attributes of a specific element, such as $scope, to a different element:

for(var k in $scope) {
  newElement[k] = $scope[k];
}

Answer 9

Answer №5

If you prefer to utilize underscore, you have the option of executing

var obj = _.extendOwn({}, $scope);

If not, simply copy the properties manually within a loop

var obj = {};

for(var k in $scope) {
    if(Object.prototype.hasOwnProperty.call($scope, k)) {
        obj[k] = $scope[k];   
    }
}

Answer 10

If you prefer to utilize underscore, you have the option of executing

var obj = _.extendOwn({}, $scope);

If not, simply copy the properties manually within a loop

var obj = {};

for(var k in $scope) {
    if(Object.prototype.hasOwnProperty.call($scope, k)) {
        obj[k] = $scope[k];   
    }
}

Answer 11

Answer №6

Here is a revised version that excludes any functions related to scope or angular variables (typically starting with $). In addition, $rootScope is injected to prevent inherited properties from transferring from $rootScope to $scope, resulting in the creation of a new object named obj.

<script>
var app = angular.module('myApp', []);
app.controller('myCtrl', function($scope, $rootScope) {
   $scope.a = "Test";
$scope.b = {x: 1, y: 2};
$scope.c = 99;
var obj = {};
angular.extend(obj, $scope);
console.log("obj is "+obj);
for(var k in $scope) {
    if(!(Object.hasOwnProperty.call($rootScope, k))) {
if(typeof $scope[k] != "function")
if(k.indexOf("$") != 0){
        obj[k] = $scope[k]; 
console.log("key is "+k);
console.log("value is "+obj[k]);  
    }
}
}
});
</script>

Answer 12

Here is a revised version that excludes any functions related to scope or angular variables (typically starting with $). In addition, $rootScope is injected to prevent inherited properties from transferring from $rootScope to $scope, resulting in the creation of a new object named obj.

<script>
var app = angular.module('myApp', []);
app.controller('myCtrl', function($scope, $rootScope) {
   $scope.a = "Test";
$scope.b = {x: 1, y: 2};
$scope.c = 99;
var obj = {};
angular.extend(obj, $scope);
console.log("obj is "+obj);
for(var k in $scope) {
    if(!(Object.hasOwnProperty.call($rootScope, k))) {
if(typeof $scope[k] != "function")
if(k.indexOf("$") != 0){
        obj[k] = $scope[k]; 
console.log("key is "+k);
console.log("value is "+obj[k]);  
    }
}
}
});
</script>

Create a duplicate of the information stored within the $scope variable

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

Answer №6

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