Transfer the value of an item from one array of objects to a different array

Question

Transfer the value of an item from one array of objects to a different array

Looking to transfer values from one array to another based on matching IDs.

array1 = [{id:1, location: 'A'},{id:2, location: 'B'},{id:3, location: 'C'},{id:4, location: 'D'}]

array2 = [{id:1, value: 123},{id:2, value: 5466},{id:3, value: 89484},{id:4, value: -4.215}]

Previous attempts at merging resulted in duplicate objects.

Desired final array structure:

array1 = [{id:1, location: 'A', value: 123},{id:2, location: 'B', value: 5466},{id:3, location: 'C', value: 89484},{id:4, location: 'D', value: -4.215}]

javascript arrays object

Answer 1

Answer №1

One way to iterate through an array is by utilizing the base array with the help of Array.prototype.map(). You can also incorporate Array.prototype.find() to search for matching values in another array based on their id:

const array1 = [{id:1, location: 'A'},{id:2, location: 'B'},{id:3, location: 'C'},{id:4, location: 'D'}],
      array2 = [{id:1, value: 123},{id:2, value: 5466},{id:3, value: 89484},{id:4, value: -4.215}],
      
      result = array1.map(o => ({...o, ...array2.find(_o => _o.id == o.id)}))
      
console.log(result)

.as-console-wrapper{min-height:100%;}

Answer 2

One way to iterate through an array is by utilizing the base array with the help of Array.prototype.map(). You can also incorporate Array.prototype.find() to search for matching values in another array based on their id:

const array1 = [{id:1, location: 'A'},{id:2, location: 'B'},{id:3, location: 'C'},{id:4, location: 'D'}],
      array2 = [{id:1, value: 123},{id:2, value: 5466},{id:3, value: 89484},{id:4, value: -4.215}],
      
      result = array1.map(o => ({...o, ...array2.find(_o => _o.id == o.id)}))
      
console.log(result)

.as-console-wrapper{min-height:100%;}

Answer 3

Answer №2

Check out the code snippet below:

var data1 = [{id:1, name: 'John'},{id:2, name: 'Jane'},{id:3, name: 'Alice'},{id:4, name: 'Bob'}]

var data2 = [{id:1, age: 25},{id:2, age: 30},{id:3, age: 28},{id:4, age: 21}]

var result = data1.map(item => {
  return {
        ...data2.filter(item2 => item2.id === item.id)[0],
        ...item
   }
})

console.log(result)

Answer 4

Check out the code snippet below:

var data1 = [{id:1, name: 'John'},{id:2, name: 'Jane'},{id:3, name: 'Alice'},{id:4, name: 'Bob'}]

var data2 = [{id:1, age: 25},{id:2, age: 30},{id:3, age: 28},{id:4, age: 21}]

var result = data1.map(item => {
  return {
        ...data2.filter(item2 => item2.id === item.id)[0],
        ...item
   }
})

console.log(result)

Answer 5

Answer №3

Here is a potential solution:

Using the map method to create a new array by merging objects from two arrays based on matching IDs.

Answer 6

Here is a potential solution:

Using the map method to create a new array by merging objects from two arrays based on matching IDs.

Answer 7

Answer №4

In the case where the indexes are the same, you can merge and spread the objects as shown below

const array1 = [{id:1, location: 'A'},{id:2, location: 'B'},{id:3, location: 'C'},{id:4, location: 'D'}];

const array2 = [{id:1, value: 123},{id:2, value: 5466},{id:3, value: 89484},{id:4, value: -4.215}];

const merged = array1.map((a,i)=>({...a, ...array2[i]}));
 
console.log(merged);

If the indexes do not match, you can use the following approach

const array1 = [{id:1, location: 'A'},{id:2, location: 'B'},{id:3, location: 'C'},{id:4, location: 'D'}];

const array2 = [{id:1, value: 123},{id:2, value: 5466},{id:3, value: 89484},{id:4, value: -4.215}];
  
const merged = array1.map(a=>({...a, ...array2.find(a2=>a2.id==a.id)}));

console.log(merged);

Answer 8

In the case where the indexes are the same, you can merge and spread the objects as shown below

const array1 = [{id:1, location: 'A'},{id:2, location: 'B'},{id:3, location: 'C'},{id:4, location: 'D'}];

const array2 = [{id:1, value: 123},{id:2, value: 5466},{id:3, value: 89484},{id:4, value: -4.215}];

const merged = array1.map((a,i)=>({...a, ...array2[i]}));
 
console.log(merged);

If the indexes do not match, you can use the following approach

const array1 = [{id:1, location: 'A'},{id:2, location: 'B'},{id:3, location: 'C'},{id:4, location: 'D'}];

const array2 = [{id:1, value: 123},{id:2, value: 5466},{id:3, value: 89484},{id:4, value: -4.215}];
  
const merged = array1.map(a=>({...a, ...array2.find(a2=>a2.id==a.id)}));

console.log(merged);

Transfer the value of an item from one array of objects to a different array

Answer №1

Answer №2

Answer №3

Answer №4

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