Tips for streamlining the array filtering process

Question

Tips for streamlining the array filtering process

Is there a way to simplify the code to avoid repetitive use of lowercase and includes condition for each property?

 items() {
  return this.table.filter.keyword
    ? this.dataArray.filter(
        item =>
          item.nombre.toLowerCase().includes(this.table.filter.keyword) ||
          item.paisOrigen
            .toLowerCase()
            .includes(this.table.filter.keyword) ||
          item.ciudad.toLowerCase().includes(this.table.filter.keyword) ||
          item.sector.toLowerCase().includes(this.table.filter.keyword) ||
          item.contratadorPor
            .toLowerCase()
            .includes(this.table.filter.keyword) ||
          item.moneda.toLowerCase().includes(this.table.filter.keyword)
      )
    : this.dataArray;
}

Appreciate any help!

javascript arrays function vue.js arrow-functions

Answer 1

Answer №1

To optimize your code, you can first use the map function followed by the filter method:

Utilize the map function to convert values to lowercase (you can utilize a for...in loop to transform all properties)
Then apply the filter on the result of the map operation.

this.data.map(item => {
  let ret = {};
  for (let p in item) {
    ret[p] = item[p].toLowerCase();
  }
  return ret;
}).filter(item => {
  //... insert your filter logic here...
});

Answer 2

To optimize your code, you can first use the map function followed by the filter method:

Utilize the map function to convert values to lowercase (you can utilize a for...in loop to transform all properties)
Then apply the filter on the result of the map operation.

this.data.map(item => {
  let ret = {};
  for (let p in item) {
    ret[p] = item[p].toLowerCase();
  }
  return ret;
}).filter(item => {
  //... insert your filter logic here...
});

Answer 3

Answer №2

To reduce repetition, consider implementing the following approach:

 items() {
  const lowerIncludes = (val) => val.toLowerCase().includes(this.table.filter.keyword)
  const fields = ['nombre', 'paisOrigen', 'ciudad', 'sector', 'contratadorPor', 'moneda']
  return this.table.filter.keyword ? this.dataArray.filter(item => fields.some(f => lowerIncludes(item[f]))) : this.dataArray
 }

Instead of repeating

.toLowerCase().includes(this.table.filter.keyword)

multiple times, encapsulate it within its own function. Define an array of fields that you want to include in the filter operation using or.

Modify

fields.some(f => lowerIncludes(item[f])

so that it functions like a series of logical OR statements. If the keyword is present in any of the specified fields, it will return true.

Answer 4

To reduce repetition, consider implementing the following approach:

 items() {
  const lowerIncludes = (val) => val.toLowerCase().includes(this.table.filter.keyword)
  const fields = ['nombre', 'paisOrigen', 'ciudad', 'sector', 'contratadorPor', 'moneda']
  return this.table.filter.keyword ? this.dataArray.filter(item => fields.some(f => lowerIncludes(item[f]))) : this.dataArray
 }

Instead of repeating

.toLowerCase().includes(this.table.filter.keyword)

multiple times, encapsulate it within its own function. Define an array of fields that you want to include in the filter operation using or.

Modify

fields.some(f => lowerIncludes(item[f])

so that it functions like a series of logical OR statements. If the keyword is present in any of the specified fields, it will return true.

Tips for streamlining the array filtering process

Answer №1

Answer №2

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