Back in the day, I would always include tons of debug code in my JavaScript app. However, I'm now searching for a method that will eliminate debug code during the compilation/minification phase.
Does the world of JavaScript have something similar to compilation directives found in C/C++?
In languages like C/C++, it typically looks like this:
#ifdef _DEBUG
counter++;
#endif
PS. At the moment, I am utilizing gulp for my development tasks.
It seems like the task you are attempting can be achieved using a task runner like grunt or gulp. These tools can convert your code with the help of plugins to perform the desired manipulation.
One such plugin is gulp-preprocess, which specifically handles the task you mentioned :)
To learn more about gulp, visit the gulp website or explore some helpful tutorials online...
Removing Debugging Statements
Erase console, alert, and debugger commands from your JavaScript code
Helpful for ensuring that no unnecessary logging is left in the final production code.
You can also find this tool as plugins for gulp, grunt, and broccoli.
How to Use
$ npm install --save strip-debug
var stripDebug = require('strip-debug');
stripDebug('function foo(){console.log("foo");alert("foo");debugger;}').toString();
//=> function foo(){void 0;void 0;}
Using with gulp
var gulp = require('gulp');
var stripDebug = require('gulp-strip-debug');
gulp.task('default', function () {
return gulp.src('src/app.js')
.pipe(stripDebug())
.pipe(gulp.dest('dist'));
});
While predominantly academic in nature, here is a pure JavaScript solution for removing certain functions from your code entirely. This approach may result in the compiled code being optimized away based on the settings of your compiler.
/** @const */
var ENABLE_ASSERTIONS = false; // change to true for debug mode
var assert = (() => ENABLE_ASSERTIONS ? () => {}: test => console.assert(test(), test.toString()))();
If ENABLE_ASSERTIONS == true, the assert function becomes an empty function: () => {}. However, if ENABLE_ASSERTIONS == false, it accepts a function as input, executes that function, and assesses the result.
Usage:
var safeDivision = function (numeratorFunc, denominatorFunc) {
assert(() => denominatorFunc() !== 0);
return numeratorFunc() / denominatorFunc();
}
This approach mimics the behavior of C-style asserts. The function within the assert only executes when ENABLE_ASSERTIONS == false. By passing a function to assert instead of an expression, we ensure that the expression inside the assert is not evaluated during production code. As a result, an optimizing compiler can potentially eliminate the assert statement as dead code.
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