This error message is indicating that there is a SyntaxError with an unexpected token 'o' when trying to

Question

This error message is indicating that there is a SyntaxError with an unexpected token 'o' when trying to

Query from AngularJS beginner:

I'm new to AngularJS and I'm attempting to utilize an asmx web service to display a grid. I have tested the web service and it correctly outputs the JSON data. Below is my controller code:

app.controller('SetupController', ['$scope', '$http', function ($scope, $http) {

    var url = 'app/pricefilessetup/grid.asmx/getGridJson';

    $http.get(url).success(function (data) {
        var myjson = JSON.parse(data);
        $scope.products= JSON.parse(myjson);
    });
}]);

Unfortunately, I am unable to paste HTML code here due to some restrictions, but it includes ng-controller directive and ng-repeat loop for parsing through the JSON data.

Upon running the application, I encounter the following error:

SyntaxError: Unexpected token o at Object.parse (native) and it points to the line below:

  $scope.questions = JSON.parse(myjson);

I attempted to check the value of myjson using alert and it displays [object Object], [object Object], ...

Is there something that I might be overlooking?

javascript json angularjs angularjs-http

Answer 1

Answer №1

It appears that the data returned is already in JSON format, so there is no need for using JSON.parse(), unless it is stored as a string.

The $scope.products variable is assigned the value of the data object.

Answer 2

It appears that the data returned is already in JSON format, so there is no need for using JSON.parse(), unless it is stored as a string.

The $scope.products variable is assigned the value of the data object.

Answer 3

Answer №2

Could you please explain the reason for using JSON.parse twice in your code?

 var myjson = JSON.parse(data);
  $scope.products = JSON.parse(myjson);

You have already parsed the data object once, so why parse it again?

Additionally, if your data is returning a JSON result, there may not be a need to parse the object.

Instead, you can simply do this:

$scope.products = data;

Answer 4

Could you please explain the reason for using JSON.parse twice in your code?

 var myjson = JSON.parse(data);
  $scope.products = JSON.parse(myjson);

You have already parsed the data object once, so why parse it again?

Additionally, if your data is returning a JSON result, there may not be a need to parse the object.

Instead, you can simply do this:

$scope.products = data;

Answer 5

Answer №3

Your myjson variable is already formatted as a JavaScript Object. No need to utilize JSON.parse on it.

Answer 6

Your myjson variable is already formatted as a JavaScript Object. No need to utilize JSON.parse on it.

Answer 7

Answer №4

An easy fix is to utilize the absolute URL:

var link = 'http://demo/app/pricefilessetup/grid.asmx/getGridJson';

Avoid using

var link = 'app/pricefilessetup/grid.asmx/getGridJson';

I have verified this method.

Answer 8

An easy fix is to utilize the absolute URL:

var link = 'http://demo/app/pricefilessetup/grid.asmx/getGridJson';

Avoid using

var link = 'app/pricefilessetup/grid.asmx/getGridJson';

I have verified this method.

Answer 9

Answer №5

One issue I encountered was passing a string literal as a parameter to the JSON.parse() function.

For instance, calling JSON.parse('asdf') would result in the following error:

Uncaught SyntaxError: Unexpected token a

.

In a specific scenario within a Single Page Application built with Angular, I was passing an access token to the JSON.parse() function. Clearing the cookies in the browser resolved the problem for me.

Answer 10

One issue I encountered was passing a string literal as a parameter to the JSON.parse() function.

For instance, calling JSON.parse('asdf') would result in the following error:

Uncaught SyntaxError: Unexpected token a

.

In a specific scenario within a Single Page Application built with Angular, I was passing an access token to the JSON.parse() function. Clearing the cookies in the browser resolved the problem for me.

This error message is indicating that there is a SyntaxError with an unexpected token 'o' when trying to

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

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