The output of an AngularJS function call is an object, not a string

Question

The output of an AngularJS function call is an object, not a string

Having trouble returning a usable string from the function below?

Here is the code:

app.factory('Urls', ['$http', function($http) {
    var urls = {};
    urls.getUrls = function () {
        return  $http.get('json/dataUrls.json'); 
    }
    return urls
}]);

app.factory('Emails', ['$http', 'Urls', function($http, Urls) {

    var dataUrl = Urls.getUrls().then(function(response) {
        return response.data.emails;
    });
    console.log(dataUrl);

    var query = {};
    query.getItems = function() {
        return  $http.get('json/emails.json');  
    };
    return query;
}]);

The result of console.log(dataUrl); shown below does not provide the desired value as a string...

f {$$state: {…}}
$$state
:
status
:
1
value
:
"json/emails.json"
__proto__
:
Object
__proto__
:
Object

javascript angularjs

Answer 1

Answer №1

Urls.fetchUrls().then(...) retrieves a promise (learn more here), which is used to store a reference to a value fetched asynchronously. When using console.log on dataUrl, an object will be returned instead of a string.

To access this value, you must do so asynchronously. The recommended approach for this is through promise chaining:

app.factory('Urls', ['$http', function($http) {
    var urls = {};
    urls.fetchUrls = function () {
        return  $http.get('json/dataUrls.json'); 
    }
    return urls
}]);

app.factory('Emails', ['$http', 'Urls', function($http, Urls) {

    Urls.fetchUrls().then(function(response) {
        return response.data.emails;
    }).then(function(emails){
        console.log(emails);
    });

    var query = {};
    query.getItems = function() {
        return  $http.get('json/emails.json');  
    };
    return query;
}]);

Answer 2

Urls.fetchUrls().then(...) retrieves a promise (learn more here), which is used to store a reference to a value fetched asynchronously. When using console.log on dataUrl, an object will be returned instead of a string.

To access this value, you must do so asynchronously. The recommended approach for this is through promise chaining:

app.factory('Urls', ['$http', function($http) {
    var urls = {};
    urls.fetchUrls = function () {
        return  $http.get('json/dataUrls.json'); 
    }
    return urls
}]);

app.factory('Emails', ['$http', 'Urls', function($http, Urls) {

    Urls.fetchUrls().then(function(response) {
        return response.data.emails;
    }).then(function(emails){
        console.log(emails);
    });

    var query = {};
    query.getItems = function() {
        return  $http.get('json/emails.json');  
    };
    return query;
}]);

Answer 3

Answer №2

When you receive DataUrls from the code snippet

var dataUrl = Urls.getUrls().then(...

, it's important to note that this is actually a Promise object, not a regular String. To achieve your desired functionality, consider the following approach:

app.factory('Urls', ['$http', function($http) {
    var urls = {};
    urls.getUrls = function () {
        return  $http.get('json/dataUrls.json'); 
    }
    return urls
}]);

app.factory('Emails', ['$http', 'Urls', function($http, Urls) {

    var query = {};
    query.getItems = function() {
        return Urls.getUrls().then(function(response) {
            return response.data.emails;
        }).then(dataUrls => { // At this point, dataUrls is a string and can be utilized accordingly.
            return  $http.get(dataUrls); 
        });
    };
    return query;
}]);

Answer 4

When you receive DataUrls from the code snippet

var dataUrl = Urls.getUrls().then(...

, it's important to note that this is actually a Promise object, not a regular String. To achieve your desired functionality, consider the following approach:

app.factory('Urls', ['$http', function($http) {
    var urls = {};
    urls.getUrls = function () {
        return  $http.get('json/dataUrls.json'); 
    }
    return urls
}]);

app.factory('Emails', ['$http', 'Urls', function($http, Urls) {

    var query = {};
    query.getItems = function() {
        return Urls.getUrls().then(function(response) {
            return response.data.emails;
        }).then(dataUrls => { // At this point, dataUrls is a string and can be utilized accordingly.
            return  $http.get(dataUrls); 
        });
    };
    return query;
}]);

Answer 5

Answer №3

app.factory('Links', ['$http', function($http) {
    var links = {};
    links.getLinks = function () {
        return  $http.get('json/dataLinks.json'); 
    }
    return links
}]);

app.factory('Contacts', ['$http', 'Links', function($http, Links) {

    Links.getLinks().then(function(response) {
        return response.data.contacts;
    }).then(function(contacts){
        console.log(contacts);
    });

    var query = {};
    query.getItems = function() {
        return  $http.get('json/contacts.json');  
    };
    return query;
}]);

Answer 6

app.factory('Links', ['$http', function($http) {
    var links = {};
    links.getLinks = function () {
        return  $http.get('json/dataLinks.json'); 
    }
    return links
}]);

app.factory('Contacts', ['$http', 'Links', function($http, Links) {

    Links.getLinks().then(function(response) {
        return response.data.contacts;
    }).then(function(contacts){
        console.log(contacts);
    });

    var query = {};
    query.getItems = function() {
        return  $http.get('json/contacts.json');  
    };
    return query;
}]);

The output of an AngularJS function call is an object, not a string

Answer №1

Answer №2

Answer №3

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