Exploring arrays to find the maximum sum of elements

Question

Exploring arrays to find the maximum sum of elements

Struggling to develop a Javascript function that identifies which element in an array of numbers (specifically phone numbers) has the highest sum? Despite feeling frustrated and defeated, I believe I am on the right track. Could someone provide some guidance on this? Below is the current state of my code:

function highest(inputArray) {
  var sum = 0;
  var currentHighest = 0;
  var largest = 0;

Initial variables are set, followed by a for loop that goes through each element in the array.

  for (a = 0; a < inputArray.length; a++)
    var tempArray = inputArray[a].replace(/\D/g,'');

A temporary string is created to eliminate non-integers from the element, and a function sums up all the digits within it.

    function sumDigits(str) {   
        for (i = 0; i < str.length; i++) {
                sum += parseInt(str.charAt(i));
        return sum;
        }
    }

An if statement is then used to determine if the current element's sum is equal to or greater than the highest sum.

    if (sumDigits(tempArray) >= currentHighest) {
          currentHighest = sum;
          largest = inputArray[a];
          return largest;
        }
        else {
            return largest;
        }
    }

var newArray = ['123-456-7777', '963-481-7945', '111-222-3333'];
console.log(highest(newArray));

Here is the summarized code:

function highest(inputArray) {
  var sum = 0;
  var currentHighest = 0;
  var largest = 0;
  for (a = 0; a < inputArray.length; a++)
    var tempArray = inputArray[a].replace(/\D/g,'');
    function sumDigits(str) {   
        for (i = 0; i < str.length; i++) {
                sum += parseInt(str.charAt(i));
        return sum;
        }
    }
    if (sumDigits(tempArray) >= currentHighest) {
          currentHighest = sum;
          largest = inputArray[a];
          return largest;
        }
        else {
            return largest;
        }
    }
}
var newArray = ['123-456-7777', '963-481-7945', '111-222-3333'];
console.log(highest(newArray));

When running the code, the output is "undefined". Any insights on that would be greatly appreciated. Thank you for your help.

javascript arrays sum compare element

Answer 1

Answer №1

If my understanding is correct (adding each digit of a phone number and then displaying the highest result), you can achieve this by following these steps:

//Create an array of phone numbers
var numbers = ['123-456-7777', '111-222-3333', '963-481-7945'];

//Using map to iterate through the array and calculate the sum of each number
var sums = numbers.map(function (m) {
    return {
        number: m,
        score: m.match(/\d/g).reduce(function (p, c) {
            return +p + +c;
        })
    }
}).sort(function (a, b) {
    if (a.score < b.score) return 1;
    if (a.score > b.score) return -1;
    return 0;
});

//Removing comments for brevity:
sums = numbers.map(function (m) {
    return {
        number: m,
        score: m.match(/\d/g).reduce(function (p, c) {
            return +p + +c;
        })
    }
}).sort(function (a, b) {
    if (a.score < b.score) return 1;
    if (a.score > b.score) return -1;
    return 0;
});

console.log(sums);

document.write("Number with the highest score: " + sums[0].number);
document.write("<br>");
document.write("Its score is " + sums[0].score);

This code snippet will display the phone number with the largest sum on the console. The total sum of digits can also be found in the returned object under the score property.

Answer 2

If my understanding is correct (adding each digit of a phone number and then displaying the highest result), you can achieve this by following these steps:

//Create an array of phone numbers
var numbers = ['123-456-7777', '111-222-3333', '963-481-7945'];

//Using map to iterate through the array and calculate the sum of each number
var sums = numbers.map(function (m) {
    return {
        number: m,
        score: m.match(/\d/g).reduce(function (p, c) {
            return +p + +c;
        })
    }
}).sort(function (a, b) {
    if (a.score < b.score) return 1;
    if (a.score > b.score) return -1;
    return 0;
});

//Removing comments for brevity:
sums = numbers.map(function (m) {
    return {
        number: m,
        score: m.match(/\d/g).reduce(function (p, c) {
            return +p + +c;
        })
    }
}).sort(function (a, b) {
    if (a.score < b.score) return 1;
    if (a.score > b.score) return -1;
    return 0;
});

console.log(sums);

document.write("Number with the highest score: " + sums[0].number);
document.write("<br>");
document.write("Its score is " + sums[0].score);

This code snippet will display the phone number with the largest sum on the console. The total sum of digits can also be found in the returned object under the score property.

Answer 3

Answer №2

Your code lacks the initialization of the sum variable and you are prematurely returning the sum value in the provided function:

function sumDigits(str) {   
    for (i = 0; i < str.length; i++) {
        sum += parseInt(str.charAt(i));
        return sum;
    }
}

To correct this issue, the function should be adjusted as follows:

function sumDigits(str) {   
    var sum = 0;
    for (i = 0; i < str.length; i++) {
        sum += parseInt(str.charAt(i), 10);
    }
    return sum;
}

Without examining the entire code as a whole, it is challenging to identify other potential problems related to how various parts of the code are interconnected and interoperate.

For a more concise solution (assuming the goal is to sum the digits in each phone number):

var phoneNumbers = ["123-456-7890", "982-111-9999"];
var sums = phoneNumbers.map(function(p) {
    return p.match(/\d/g).reduce(function(sum, num) {
        return sum + parseInt(num, 10);
    }, 0);
});
var maxSum = Math.max.apply(Math, sums);

// display results in the snippet window                    
document.write("sums = " + JSON.stringify(sums) + "<br>");
document.write("maxSum = " + maxSum + "<br>");

Here is how this solution operates:

Utilize .map() on the phone numbers array to generate an array of sums.
Within the .map(), identify all digits, then execute .reduce() on the obtained array to accumulate the sum.
For determining the maximum value in the sums array, utilize Math.max(), which can handle the entire array and determine the maximum value efficiently.

Answer 4

Your code lacks the initialization of the sum variable and you are prematurely returning the sum value in the provided function:

function sumDigits(str) {   
    for (i = 0; i < str.length; i++) {
        sum += parseInt(str.charAt(i));
        return sum;
    }
}

To correct this issue, the function should be adjusted as follows:

function sumDigits(str) {   
    var sum = 0;
    for (i = 0; i < str.length; i++) {
        sum += parseInt(str.charAt(i), 10);
    }
    return sum;
}

Without examining the entire code as a whole, it is challenging to identify other potential problems related to how various parts of the code are interconnected and interoperate.

For a more concise solution (assuming the goal is to sum the digits in each phone number):

var phoneNumbers = ["123-456-7890", "982-111-9999"];
var sums = phoneNumbers.map(function(p) {
    return p.match(/\d/g).reduce(function(sum, num) {
        return sum + parseInt(num, 10);
    }, 0);
});
var maxSum = Math.max.apply(Math, sums);

// display results in the snippet window                    
document.write("sums = " + JSON.stringify(sums) + "<br>");
document.write("maxSum = " + maxSum + "<br>");

Here is how this solution operates:

Utilize .map() on the phone numbers array to generate an array of sums.
Within the .map(), identify all digits, then execute .reduce() on the obtained array to accumulate the sum.
For determining the maximum value in the sums array, utilize Math.max(), which can handle the entire array and determine the maximum value efficiently.

Exploring arrays to find the maximum sum of elements

Answer №1

Answer №2

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