The Javascript array transforms into null

Question

The Javascript array transforms into null

I have created a two-dimensional array and attempted to fill it using a nested loop. However, only the first dimension is being populated with the correct values while the other dimensions remain filled with null or undefined. Any suggestions on how to rectify this issue would be greatly appreciated.

var Arr = [];
var i = 0;

for (i = 0; i < 13; i++) {
  Arr[i] = [];
}

var a = 0, b = 0;

for (a = 0; a < 13; a++) {
  for (b = 0; b < 13; b++) {
    Arr[[a][b]] = AnotherArrWithRightValues[(13 * a) + b];
  }
}

javascript arrays

Answer 1

Answer №1

Instead of Arr[[a][b]], you should write Arr[a][b]

Answer 2

Instead of Arr[[a][b]], you should write Arr[a][b]

Answer 3

Answer №2

Although Loksly's response is accurate, it offers a fresh approach to achieve the same result. In order to address your inquiry, simply substitute Arr[[a][b]] with Arr[a][b].

Complete Code :

var Arr = [];

for(let a = 0 ; a < 13 ; a++) {
  Arr[a] = [];
  for(let b = 0 ; b < 13 ; b++) {
    Arr[a][b]=AnotherAppropriateArr[(13 * a) + b];
  }
}

Answer 4

Although Loksly's response is accurate, it offers a fresh approach to achieve the same result. In order to address your inquiry, simply substitute Arr[[a][b]] with Arr[a][b].

Complete Code :

var Arr = [];

for(let a = 0 ; a < 13 ; a++) {
  Arr[a] = [];
  for(let b = 0 ; b < 13 ; b++) {
    Arr[a][b]=AnotherAppropriateArr[(13 * a) + b];
  }
}

Answer 5

Answer №3

Here is an alternative method to achieve the same result:

let myArray = [];
let index = 0, temp;
let x, y;

for(x = 0; x < 13; x++){
    temp = [];
    for(y = 0; y < 13; y++){
       temp.push(valuesFromAnotherArray[index++]);
    }
    myArray.push(temp);
}

Answer 6

Here is an alternative method to achieve the same result:

let myArray = [];
let index = 0, temp;
let x, y;

for(x = 0; x < 13; x++){
    temp = [];
    for(y = 0; y < 13; y++){
       temp.push(valuesFromAnotherArray[index++]);
    }
    myArray.push(temp);
}

Answer 7

Answer №4

Give this a shot:

let newArray = [];

for(let x=0;x<13;x++)
  {
    newArray[x] = new Array();
    for(let y=0;y<13;y++)
      {
        newArray[x].push((13 * x) + y);
      }
  }

Hopefully, this solution serves your needs.

Answer 8

Give this a shot:

let newArray = [];

for(let x=0;x<13;x++)
  {
    newArray[x] = new Array();
    for(let y=0;y<13;y++)
      {
        newArray[x].push((13 * x) + y);
      }
  }

Hopefully, this solution serves your needs.

The Javascript array transforms into null

Answer №1

Answer №2

Answer №3

Answer №4

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