Having an issue with moving all DOM elements from one node to another, I initially used this code:
div.childNodes.forEach((n) => me.container.appendChild(n));
However, I noticed that only half of the nodes were being copied. It seems that the problem lies in how JavaScript is handling the iteration internally, similar to a standard for loop:
for(let i = 0; i < div.childNodes.length; i++) {
me.container.appendChild(div.childNodes[i]);
}
This behavior occurs because the length of div.childNodes decreases every time an item is appended to me.container.
Even the following approach encounters the same issue:
for (const n of div.childNodes) {
me.container.appendChild(n);
}
The question now arises: what is the best practice to avoid such bugs when moving DOM elements, and can we trust JavaScript's functional functions to perform as intended?
I have discovered two solutions that work, but I am curious if there is a noticeable difference in speed between them. Personally, I lean towards the first option as it appears more straightforward:
Array.from(div.childNodes).forEach((n) => me.container.appendChild(n));
Alternatively, without converting the nodes:
for (let i = div.childNodes.length; i > 0; i--) {
me.container.appendChild(div.childNodes[0]);
}
Both approaches successfully copy all the nodes without any issues.