Sorting an array of strings that contain years in JavaScript

Question

Sorting an array of strings that contain years in JavaScript

I am attempting to organize an array of seasons based on season and year, all while eliminating any duplicate seasons. Merely sorting the array did not produce the desired outcome, so I believe utilizing a regex might solve the issue.

const myStringArray = ["Winter 17", "Summer 13", "Winter 15", "Summer 12", "Winter 17", "Summer 12", "Summer 17"]
     
console.log(_.uniq(myStringArray).sort(function(a, b) {
    return b - a;                                  
}));

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.min.js"></script>

javascript lodash

Answer 1

Answer №1

If you want to achieve this, you can follow the code snippet below:

const monthsArray = ["Winter 17", "Summer 13", "Winter 15", "Summer 12", "Winter 17", "Summer 12", "Summer 17"]

console.log(_.uniq(monthsArray).sort(function(a, b) {
  return b.split(' ')[1] - a.split(' ')[1] || a.localeCompare(b);
}));

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.min.js"></script>

Answer 2

If you want to achieve this, you can follow the code snippet below:

const monthsArray = ["Winter 17", "Summer 13", "Winter 15", "Summer 12", "Winter 17", "Summer 12", "Summer 17"]

console.log(_.uniq(monthsArray).sort(function(a, b) {
  return b.split(' ')[1] - a.split(' ')[1] || a.localeCompare(b);
}));

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.min.js"></script>

Answer 3

Answer №2

To organize by year, you can use the index of a specified array to arrange seasons in order. To ensure uniqueness within the array, employ a new Set.

const myStringArray = [...new Set(["Winter 17", "Summer 13", "Winter 15", "Summer 12", "Winter 17", "Summer 12", "Summer 17"])];
const order = ['Winter', 'Summer', 'Fall', 'Spring'];

myStringArray.sort((a, b) => {
  let s = b.split(/\s/);
  let s1 = a.split(/\s/);
  return Number(s1[1]) - Number(s[1]) || order.indexOf(s[0]) * -1;
});

console.log(myStringArray);

Answer 4

To organize by year, you can use the index of a specified array to arrange seasons in order. To ensure uniqueness within the array, employ a new Set.

const myStringArray = [...new Set(["Winter 17", "Summer 13", "Winter 15", "Summer 12", "Winter 17", "Summer 12", "Summer 17"])];
const order = ['Winter', 'Summer', 'Fall', 'Spring'];

myStringArray.sort((a, b) => {
  let s = b.split(/\s/);
  let s1 = a.split(/\s/);
  return Number(s1[1]) - Number(s[1]) || order.indexOf(s[0]) * -1;
});

console.log(myStringArray);

Answer 5

Answer №3

If your strings will always be in the format <Season YY> and digits occur only once, you can easily organize them in descending order using a straightforward regex approach:

const myStringArray = ["Winter 17", "Summer 13", "Winter 15", "Summer 12", "Winter 17", "Summer 12", "Summer 17"]
     
console.log(_.uniq(myStringArray).sort(function(a, b) {
    return +b.match(/\d+/)[0] - +a.match(/\d+/)[0];                                  
}));

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.min.js"></script>

Answer 6

If your strings will always be in the format <Season YY> and digits occur only once, you can easily organize them in descending order using a straightforward regex approach:

const myStringArray = ["Winter 17", "Summer 13", "Winter 15", "Summer 12", "Winter 17", "Summer 12", "Summer 17"]
     
console.log(_.uniq(myStringArray).sort(function(a, b) {
    return +b.match(/\d+/)[0] - +a.match(/\d+/)[0];                                  
}));

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.min.js"></script>

Sorting an array of strings that contain years in JavaScript

Answer №1

Answer №2

Answer №3

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