Sort the collection of words by their corresponding suffixes

Question

Sort the collection of words by their corresponding suffixes

Looking to use JavaScript to compare two lists and extract words from WORDLIST that end with the characters in END (not in the middle of the word). I am also open to using jQuery for this task.

var WORDLIST = ['instagrampost', 'facebookpost', 'google']
var END = ['post', 'gle']

function compare() {
    var final = WORDLIST.endsWith(END, END.length);
    console.log(final);
}

// To do: count signs at end
// Extract words from end of WORDLIST based on length of END
// Save any matching words from WORDLIST as results

javascript arrays

Answer 1

Answer №1

To filter your list of words, called WORDLIST, based on whether any item in the array END is a valid ending for a word, you can use the Array.prototype.some() method along with the String.prototype.endsWith() function:

const WORDLIST = ['instagrampost', 'facebookposting', 'google'],
      END = ['post', 'gle'],

      result = WORDLIST.filter(word =>
        END.some(end => word.endsWith(end)))
        
console.log(result)

Note: For case-insensitive matching, you can convert both the word and the ending to lowercase before using endsWith() like this:

word.toLowerCase().endsWith(end.toLowerCase())

Answer 2

To filter your list of words, called WORDLIST, based on whether any item in the array END is a valid ending for a word, you can use the Array.prototype.some() method along with the String.prototype.endsWith() function:

const WORDLIST = ['instagrampost', 'facebookposting', 'google'],
      END = ['post', 'gle'],

      result = WORDLIST.filter(word =>
        END.some(end => word.endsWith(end)))
        
console.log(result)

Note: For case-insensitive matching, you can convert both the word and the ending to lowercase before using endsWith() like this:

word.toLowerCase().endsWith(end.toLowerCase())

Answer 3

Answer №2

Here's a non-regex solution that uses the indexOf method:

var WORDLIST = ['instagrampost', 'facele', 'facebookpost', 'google', 'dnuiwa']
var END = ['post', 'gle']

function endsWith(wordlist, end){
  return wordlist.filter((w) =>
    end.filter((e) => w.indexOf(e) == w.length - e.length).length > 0
  );
}

console.log(endsWith(WORDLIST, END))

Answer 4

Here's a non-regex solution that uses the indexOf method:

var WORDLIST = ['instagrampost', 'facele', 'facebookpost', 'google', 'dnuiwa']
var END = ['post', 'gle']

function endsWith(wordlist, end){
  return wordlist.filter((w) =>
    end.filter((e) => w.indexOf(e) == w.length - e.length).length > 0
  );
}

console.log(endsWith(WORDLIST, END))

Sort the collection of words by their corresponding suffixes

Answer №1

Answer №2

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