Rearrange the elements of an array without altering the original

Question

Rearrange the elements of an array without altering the original

Looking for a way in JavaScript to sort an array without altering the element order but creating a "grouping" feature.

Example Data:

[
  {group: 'test',  title: 'A'},
  {group: 'test',  title: 'B'},
  {group: 'test2', title: 'C'},
  {group: 'test',  title: 'D'}
]

The goal is to use [].sort() to achieve this final order:

[
  {group: 'test',  title: 'A'},
  {group: 'test',  title: 'B'},
  {group: 'test',  title: 'D'},
  {group: 'test2', title: 'C'}
]

This means not changing the order of the first two items, only switching #3 and #4 based on their group. Using localeCompare would reorganize the groups alphabetically, which is not desired; their original order should be maintained.

UPDATE: To clarify further, I do not want to rearrange the group order alphabetically, they should remain in the same sequence as they appear.

javascript sorting

Answer 1

Answer №1

It is essential to implement a custom comparison function when using Array.sort

let data = [
  {category: 'example', name: 'A'},
  {category: 'example', name: 'B'},
  {category: 'demo', name: 'C'},
  {category: 'example', name: 'D'}
];

function customComparison(a1, b1) {
    return a1.category < b1.category ? -1 : a1.category === b1.category ? 0 : 1;
}

data.sort(customComparison);

console.log(data);

Answer 2

It is essential to implement a custom comparison function when using Array.sort

let data = [
  {category: 'example', name: 'A'},
  {category: 'example', name: 'B'},
  {category: 'demo', name: 'C'},
  {category: 'example', name: 'D'}
];

function customComparison(a1, b1) {
    return a1.category < b1.category ? -1 : a1.category === b1.category ? 0 : 1;
}

data.sort(customComparison);

console.log(data);

Answer 3

Answer №2

Give this a shot:

function sortTitles(bookA, bookB) {
  if (bookA.title < bookB.title)
     return -1;
  if (bookA.title > bookB.title)
    return 1;
  return 0;
}

books.sort(sortTitles);

Answer 4

Give this a shot:

function sortTitles(bookA, bookB) {
  if (bookA.title < bookB.title)
     return -1;
  if (bookA.title > bookB.title)
    return 1;
  return 0;
}

books.sort(sortTitles);

Answer 5

Answer №3

To tackle this sorting challenge, you can implement a comparison function like the following:

function customSort(a, b) {
  if (a.category == b.category) {
    return a.name < b.name ? -1 : a.name == b.name ? 0 : 1;
  }
  return a.category < b.category ? -1 : 1;
}

yourArray.sort(customSort)

If I correctly interpreted your query, you aim to first sort by categories and then by name within the same category.

Answer 6

To tackle this sorting challenge, you can implement a comparison function like the following:

function customSort(a, b) {
  if (a.category == b.category) {
    return a.name < b.name ? -1 : a.name == b.name ? 0 : 1;
  }
  return a.category < b.category ? -1 : 1;
}

yourArray.sort(customSort)

If I correctly interpreted your query, you aim to first sort by categories and then by name within the same category.

Rearrange the elements of an array without altering the original

Answer №1

Answer №2

Answer №3

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