RegEx - Finding exact matches without any additional characters trailing

I am currently trying to find matches in the given strings:

'Los Angeles, CA'
'New York, NY'
'Williamsburg, Brooklyn, NY'

by comparing them with the following input strings:

'Los Angeles, CA 90001, USA'
'New York, NY 10017, USA'
'Williamsburg, Brooklyn, NY, USA'

This task is being tackled using JavaScript. Here's what I have so far:

var re = /.+[A-Z]{2}( |,)/,
    location = '',  // Insert address string here
    substring = location.match(re)[0];  // This will return something like Williamsburg, Brooklyn, NY,

While the regular expression above successfully matches the examples provided, it leaves a trailing whitespace or comma at the end depending on the string. I could use slice() to remove the trailing character, but I am wondering if this can be achieved within the regex itself. Is it possible?

Answer №1

Instead of using a capturing group ( ) that includes the space character or comma in the match, you can utilize a Positive Lookahead.

var re = /.+[A-Z]{2}(?= |,)/

Check out the Live demo

Answer №2

One alternative method is to implement the word boundary .+\b[A-Z]{2}\b

Answer №3

Other Options :

substring = location.split(/([A-Z]{2})/, 2).join('');
substring = location.slice(0, location.search(/[A-Z]{2}/) + 2);

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