Performing a targeted ajax request to retrieve a set of data

Is it possible to create a collection using a specific ajax call instead of fetching by its URL? Normally, when fetching by a collection, the URL in the collection is used. However, I need to retrieve results from an ajax call rather than the URL.

$.ajax({
type: 'GET',
headers: {'X-Parse-Application-Id':'qS0KLM***EM1tyhM9EEPiTS3VMk','X-Parse- 
REST-API-Key':'nh3eoUo9G8Df****vbF2gMhcKJIfIt1Gm'},
url: "https://api.parse.com/1/classes/_User/",

data: 'where={"amici": 
{"__type":"Pointer","className":"_User","objectId":"g0fRKnrgZN"}}',//restituisce chi ha   
negli amici l'id objectId
//contentType: "application/json",

success: function(data) {
      console.log(data );

    },
    error: function(data) {

      console.log("ko" );
    }



});

I'm looking to build my collection based on this particular ajax call.

Answer №1

If you need to customize the fetch call options, here's how:

yourCollection.fetch({url: newUrl})

Alternatively, you can do it like this:

yourCollection.fetch = function(options) {
    return this.constructor.__super__.fetch.call(this, _.extend({url: newUrl}, options));
};

If you want to modify the fetch call for yourCollection throughout a View, you can simply use yourCollection.fetch() without specifying the newUrl parameter.

I hope you find this helpful.

Answer №2

Option A) Overwrite the fetch method in your current collection:

fetch: function(options) {
            // add any additional code here
            //..
            // make sure to include this line if you want to keep the original fetch functionality
            //return Backbone.Collection.prototype.fetch.call(this, options);
},

Option B) For a universal solution across all collections:

Create a new object YourCollection that extends Backbone.Collection, and override the fetch method within this new object. Subsequently, have your new collections extend YourCollection rather than directly inheriting from Backbone.Collection.

Note: Additionally, if necessary, adjust the behavior of the ajax call:

    var ajax = $.ajax;

    $.ajax = function(url, options) {
       //insert your modifications here
       return ajax.call(this, url, options);
    };

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