Obtain a string value from a JavaScript object

Question

Obtain a string value from a JavaScript object

My dilemma involves a specific Javascript object.

{
    A: 1,
    B: 2,
    C: 2,
    D: 1,
    E: 1,
    F: 4,
    G: 6,
    H: 2
},

The goal is to extract a four-letter string based on the key with the highest value, but there are limitations. The string must be constructed from one of the following 16 combinations in their specified order:

A or B
C or D
E or F
G or H

This means there are only 16 possible combinations. Using the above example would yield the string "BCFG".

Has anyone come up with a solution?

javascript

Answer 1

Answer №1

To achieve this task, you can:

Extract the entries of the object,
Combine pairs of entries,
Determine which entry has a greater value,
Concatenate all values into a single string.

var object = { A: 1, B: 2, C: 2, D: 1, E: 1, F: 4, G: 6, H: 2 },
    result = Object
        .entries(object)
        .reduce((r, a, i) => {
            if (i % 2) {
               r[r.length - 1].push(a);
            } else {
                r.push([a]);
            }
            return r;
        }, [])
        .map(([a, b]) => a[1] > b[1] ? a[0] : b[0])
        .join('');

console.log(result);

Answer 2

To achieve this task, you can:

Extract the entries of the object,
Combine pairs of entries,
Determine which entry has a greater value,
Concatenate all values into a single string.

var object = { A: 1, B: 2, C: 2, D: 1, E: 1, F: 4, G: 6, H: 2 },
    result = Object
        .entries(object)
        .reduce((r, a, i) => {
            if (i % 2) {
               r[r.length - 1].push(a);
            } else {
                r.push([a]);
            }
            return r;
        }, [])
        .map(([a, b]) => a[1] > b[1] ? a[0] : b[0])
        .join('');

console.log(result);

Answer 3

Answer №2

I evaluate each pair of items within the object and then create a string based on the higher value in each pair.

const obj = { A: 3, B: 4, C: 2, D: 5, E: 6, F: 3, G: 2, H: 1 } //"BDEG"

let findHighest = (obj) => {
  let result = "";
  // Transform the object into an array
  obj = Object.keys(obj).map(function(key) {
    return [key, obj[key]];
  });
  // Loop through the array with increments of 2
  for (let i = 0, len = obj.length; i < len; i += 2){
    // Compare values of two elements at a time
    if (obj[i][1] > obj[i+1][1]){
      result += obj[i][0];
    }
    else {
      result += obj[i+1][0];
    }
  }
  return result;
}

console.log(findHighest(obj));

Answer 4

I evaluate each pair of items within the object and then create a string based on the higher value in each pair.

const obj = { A: 3, B: 4, C: 2, D: 5, E: 6, F: 3, G: 2, H: 1 } //"BDEG"

let findHighest = (obj) => {
  let result = "";
  // Transform the object into an array
  obj = Object.keys(obj).map(function(key) {
    return [key, obj[key]];
  });
  // Loop through the array with increments of 2
  for (let i = 0, len = obj.length; i < len; i += 2){
    // Compare values of two elements at a time
    if (obj[i][1] > obj[i+1][1]){
      result += obj[i][0];
    }
    else {
      result += obj[i+1][0];
    }
  }
  return result;
}

console.log(findHighest(obj));

Answer 5

Answer №3

var data = {
    X: 3,
    Y: 4,
    Z: 1,
    W: 5,
    P: 2,
    Q: 6,
    R: 2,
    S: 3
};

var output = Object.keys(data).reduce(function(output, item, position, list) {
  if (position % 2 === 0) {
    output.push(list[data[item] > data[list[position + 1]] ? position : position + 1])
  }
  return output;
}, []).join('');

Answer 6

var data = {
    X: 3,
    Y: 4,
    Z: 1,
    W: 5,
    P: 2,
    Q: 6,
    R: 2,
    S: 3
};

var output = Object.keys(data).reduce(function(output, item, position, list) {
  if (position % 2 === 0) {
    output.push(list[data[item] > data[list[position + 1]] ? position : position + 1])
  }
  return output;
}, []).join('');

Answer 7

Answer №4

let values = { A: 1, B: 2, C: 2, D: 1, E: 1, F: 4, G: 6, H: 2 }
let characters = [];
let nums = [];
let result = "";

for (let key in values) {
    characters.push(key);
    nums.push(values[key]);
}

for (let i = 1; i < characters.length; i += 2) {
    if (nums[i-1] > nums[i]) {
        result = result + characters[i-1];
    } else {
        result = result + characters[i];
    }
}

This method provides a basic solution to the problem at hand. By organizing data into arrays and working in pairs, you can achieve the desired outcome.

While there are more complex strategies available, they may not be suitable for educational purposes ;)

Answer 8

let values = { A: 1, B: 2, C: 2, D: 1, E: 1, F: 4, G: 6, H: 2 }
let characters = [];
let nums = [];
let result = "";

for (let key in values) {
    characters.push(key);
    nums.push(values[key]);
}

for (let i = 1; i < characters.length; i += 2) {
    if (nums[i-1] > nums[i]) {
        result = result + characters[i-1];
    } else {
        result = result + characters[i];
    }
}

This method provides a basic solution to the problem at hand. By organizing data into arrays and working in pairs, you can achieve the desired outcome.

While there are more complex strategies available, they may not be suitable for educational purposes ;)

Obtain a string value from a JavaScript object

Answer №1

Answer №2

Answer №3

Answer №4

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