Obtain a specific amount of values from arrayA[5000] and transfer them into arrayB[] grouped together

Question

Obtain a specific amount of values from arrayA[5000] and transfer them into arrayB[] grouped together

My array looks like this:

 arrayA = [1,2,3,4,5,6,7,8,9,1,2,3,4,5,6,7,8,9,1,2];

I want to organize the numbers into groups like this:

arrayB = [1234,5678,9123,4567,8912];

Essentially, I need to take the values from arrayA and create new numbers by grouping 4 numbers together.

My current code has a bug where the output looks like this:

arrayB=[undefined1234,undefined5678];

This is the code I used:

for (var i = 0; i < 20; i++) {
        if (i/4== n+1){
            arrayB[n] = temp;
            n++;
        }
         temp += arrayA[i];
}

I recognize that the bug is due to the += operator, but I'm unsure how to resolve it.

javascript arrays loops

Answer 1

Answer №1

By utilizing this script, you can achieve the desired outcome

        var numbers = [10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120];
        var updatedNumbers = [];
        for (var i = 0; i < numbers.length; i += 5) {
           updatedNumbers.push(numbers.slice(i, i + 5).join(''));
        }

        console.log(updatedNumbers);

Additional Information
After receiving a suggestion from Mike, it's now recommended to include the following code in the for loop for numerical values in the result array

updatedNumbers.push(parseInt(numbers.slice(i, i + 5).join('')));

Answer 2

By utilizing this script, you can achieve the desired outcome

        var numbers = [10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120];
        var updatedNumbers = [];
        for (var i = 0; i < numbers.length; i += 5) {
           updatedNumbers.push(numbers.slice(i, i + 5).join(''));
        }

        console.log(updatedNumbers);

Additional Information
After receiving a suggestion from Mike, it's now recommended to include the following code in the for loop for numerical values in the result array

updatedNumbers.push(parseInt(numbers.slice(i, i + 5).join('')));

Answer 3

Answer №2

Consider initializing the variable temp as an empty string before the loop begins, and reinitialize it as an empty string each time you assign a value to the variable arrayB (ensuring to convert the string in the variable step to an integer). Additionally, you may need to make a final assignment to the variable arrayB after the completion of the for loop.

Answer 4

Consider initializing the variable temp as an empty string before the loop begins, and reinitialize it as an empty string each time you assign a value to the variable arrayB (ensuring to convert the string in the variable step to an integer). Additionally, you may need to make a final assignment to the variable arrayB after the completion of the for loop.

Answer 5

Answer №3

This is my approach:

numArray = [1, 2, 3, 4, 5, 6, 7, 8, 9, 1, 2, 3, 4, 5, 6, 7, 8, 9, 1, 2];
tempString = numArray.join('');

groupSize = 4;

groupedNums = [];

maxIndex = tempString.length / groupSize;

for (j = 0; j < maxIndex; j++) {

  groupedNums.push(parseInt(tempString.substr(j * 4, 4)));

}

console.log(groupedNums);

Simple conversion from numbers to strings and then back to numbers. :) Check out the demo here: http://jsfiddle.net/hue0a1wb/

Answer 6

This is my approach:

numArray = [1, 2, 3, 4, 5, 6, 7, 8, 9, 1, 2, 3, 4, 5, 6, 7, 8, 9, 1, 2];
tempString = numArray.join('');

groupSize = 4;

groupedNums = [];

maxIndex = tempString.length / groupSize;

for (j = 0; j < maxIndex; j++) {

  groupedNums.push(parseInt(tempString.substr(j * 4, 4)));

}

console.log(groupedNums);

Simple conversion from numbers to strings and then back to numbers. :) Check out the demo here: http://jsfiddle.net/hue0a1wb/

Obtain a specific amount of values from arrayA[5000] and transfer them into arrayB[] grouped together

Answer №1

Answer №2

Answer №3

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