I am encountering an issue with my code. I intend for it to display:
aaa bbb ccc ddd
However, it currently shows:
Undefined bbb Undefined ddd
Is there a way to ensure that test3 is correctly defined outside of the aaa function?
var test1;
var test2;
var test3 = test1 + ' bbb ' + test2 + ' ddd';
var aaa = function() {
var test1 = "aaa";
var test2 = "ccc";
alert(test3);
}
aaa();
It is crucial to initialize the variables test1 and test2 before utilizing them to set a value for test3. Otherwise, they will be undefined when you attempt to assign a value to test3. Consequently, test3 will not dynamically update with changes made to test1 and test2.
var test3;
var aaa = function() {
var test1 = "aaa";
var test2 = "ccc";
test3 = test1 + ' bbb ' + test2 + ' ddd';
alert(test3);
}
aaa();
To ensure that test3 reflects dynamically updated values, it can be defined as a function:
var test3 = function (test1, test2) {
return test1 + ' bbb ' + test2 + ' ddd';
};
var aaa = function () {
alert(test3('aaa', 'bbb'));
};
aaa();
Make sure to update the value of test3.
For further information, check out: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Guide/Grammar_and_types#Declarations
experiment3 does not automatically recognize that experiment1 and experiment2 have been given values; you must assign the variables again.
It is recommended to keep it specified externally, but make sure to initialize it after defining test1 and test2:
let test1, test2, test3;
let aaa = function() {
test1 = "aaa";
test2 = "ccc";
test3 = test1 + ' bbb ' + test2 + ' ddd';
alert(test3);
}
aaa();An improved approach to this problem could involve creating a function that assigns values to those variables. Here is a simple code snippet suitable for beginners:
var variable1 = assignValue('aaa');
var variable2 = assignValue('ccc');
var finalResult = variable1 + ' bbb ' + variable2 + ' ddd';
function assignValue(value) {
console.log(value);
return value;
}
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