Match one instance of a character in a regular expression pattern while simultaneously matching two occurrences of a different character

I am attempting to create a function that can match one occurrence of a certain character and two occurrences of another character simultaneously. For instance, in the string "_Hell_o", I want to match the first underscore (_) and in the string "++Hello", I need to match both plus signs (+). Ideally, the function would look like this:

function check(str) {
    console.log(str.replace(/[_+{2}]/, ''));
}

check("++Hello");
check("_Hello");
check("+Hello");

The expected outputs are supposed to be:

>>> Hello
>>> Hello
>>> +Hello

However, this particular function is not functioning correctly.

Answer №1

/^_{1}|\+{2}/g is the solution here.

function modifyString(str){
    console.log(str.replace(/^_{1}|\+{2}/g, ''));
}

modifyString("++Goodbye");
modifyString("+++Goodbye");
modifyString("_Goo__dby_e");
modifyString("___Goodbye");
modifyString("+Goodbye");

Answer №2

If you're looking to resolve your issue, consider using a dual-replace method like this:

var items = ["--Goodbye", "_Goodbye", "-Goodbye"];
for (var j = 0; j < items.length; j++) {
    console.log(items[j].replace(/\-{2}/, '').replace(/_(.*)/, '$1'))
}

Answer №3

str.replace('++', '').replace('_', '')

This edited response, inspired by YCF_L's solution, effectively eliminates the initial instance of ++ and _.

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