Trying to multiply all the elements of array A, however, with values [1,2,0,-5], it should return 0 but it actually returns 1. What mistake am I making? Here is the code:
function solution(A){
let multi = 1;
for(i = 1; i < A.length; i++){
multi *= A[i]
}
if(multi == 30){
return 1
} else if (multi == -30){
return -1
} else if (multi == 0){
return 0
} else{
console.log("hey hey");
}
}
solution(A = [1,2,0,-5])
Your loop should always start at 0 in JavaScript arrays, which are 0-indexed. Also, make sure to use the comparison operator == instead of the assignment operator = in your if conditions.
function calculateProduct(array){
let product = 1;
for(i = 0; i < array.length; i++){
product *= array[i]
}
if(product == 30){
return 1
} else if (product == -30){
return -1
} else if (product == 0){
return 0
} else{
console.log("hey hey");
}
}
In the world of Javascript, arrays have a unique starting point at 0 instead of 1. If this concept is causing confusion, consider using the "reduce" function to effectively multiply the elements of an array without having to worry about indices.
let mult = A.reduce((a,b)=>a*b);
It's important to note that in the statement "if(multi=30)", there is an assignment happening rather than a comparison. This results in evaluating whether multi is actually non-zero, as it holds the value of 30. To prevent this issue, consider placing the constant on the left side like so:-
if(30 === multi){
return 1
} else if (-30 ===multi){
return -1
} else if (0===multi){
return 0
} else{
console.log("hey hey");
}
Another helpful tip is to remember that when passing values to functions, they are based on position rather than naming parameters directly.
solution([1,2,0,-5]);
function calculateProduct(A){
const product = A.reduce((a, b) => a*b);
return product == 30 ? 1 : product == -30 ? -1 : 0;
}
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