Is there a way to transform a string into an array that merges the elements together consecutively?

Question

Is there a way to transform a string into an array that merges the elements together consecutively?

Imagine having a string formatted like this:

const name = "Matt"

Now, you want to transform it into an array like the following:

nameSearchArr = [
0: "M",
1: 'Ma',
2: 'Mat',
3: 'Matt
]

To work around Firestore's lack of 'full text search' functionality, I am looking to create an array and utilize 'array-contains' for searching names. This way, while typing in a name, it will match with the elements in the nameSearchArr. Does anyone have recommendations on the best approach to achieve this? Thank you in advance!

javascript arrays firebase algorithm full-text-search

Answer 1

Answer №1

Utilizing the slice method provides a refined solution.

function extractStringParts(input) {
   const output = [];
   for (let j = 0; j < input.length; j++) {
      output.push(input.slice(0, j));
   }
   return output;
}

const phrase = "Hello";
console.log(extractStringParts(phrase));

Answer 2

Utilizing the slice method provides a refined solution.

function extractStringParts(input) {
   const output = [];
   for (let j = 0; j < input.length; j++) {
      output.push(input.slice(0, j));
   }
   return output;
}

const phrase = "Hello";
console.log(extractStringParts(phrase));

Answer 3

Answer №2

Although this may not be the perfect solution for tackling the issue of 'full text search', the following code snippet might just work:

const greeting = "Hello"

const output = greeting.split("").map((letter, index) => greeting.slice(0,index+1))

console.log(output)

Answer 4

Although this may not be the perfect solution for tackling the issue of 'full text search', the following code snippet might just work:

const greeting = "Hello"

const output = greeting.split("").map((letter, index) => greeting.slice(0,index+1))

console.log(output)

Is there a way to transform a string into an array that merges the elements together consecutively?

Answer №1

Answer №2

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