Is there a way to extract the URL from an ng-resource?

Is there a way to retrieve the URL and parameters from an ng-resource object?

If not, what are some strategies for creating a custom wrapper or extending ng-resource to achieve this functionality?

Update: My goal is to extract the URL and params from the resource object without making an actual request.

In an ideal scenario, I would like the following to work:

myResource = $resource('localhost/foo/bar');

myResource.getUrl() // returns localhost/foo/bar

Since the getUrl function doesn't exist, I attempted a solution mentioned in

An example of using a wrapping factory:

angular.module('app').factory('ExtendedResourceFactory',['$resource',
  function($resource) {
    function ExtendedResourceFactory() {
      var Resource = $resource.apply(this, arguments);

      Resource.prototype.getArguments = function() {
        return arguments
      };

      return Resource;
    }

    return ExtendedResourceFactory;
  }
]); 

I integrated the new factory and tested it:

res = ExtendedResourceFactory('url')
res.getArguments()

Uncaught TypeError: res.getArguments is not a function(…) 

Any suggestions or solutions would be greatly appreciated!

Answer №1

If you are looking for a solution, this might help. By having control over the URL passed into $resource, you can customize the response to fit your needs. While it may not be the most elegant solution, it does get the job done.

let customResource;

customResource = $resource('/example/resource', 
  {
    id: 1
  }, {
    get: {
      method: 'GET',
      transformResponse: function(data) {
        data = angular.fromJson(data);
        data.getCustomUrl = function() {
          return '/example/resource';
        };
        return data;
      }
    }
  }
);

Answer №2

NgResource seems to keep all its internal variables and URLs within its scope, preventing external access.

One workaround is to enhance your $resource with custom information that you specify. By doing this, you can include additional properties like URLs directly in your resource.

myResource = angular.extend(
    $resource('localhost/foo/bar'),
    { 
        getUrl: function() { return 'localhost/foo/bar'; }
    }
);
myResource.getUrl() // returns localhost/foo/bar

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