Why does parseInt behave differently with -0 in JavaScript?
parseInt(-0, 10) // 0
parseInt('-0', 10) // -0
Is there a specific rationale behind this inconsistency or is it simply a quirky feature of JavaScript?
Why does parseInt behave differently with -0 in JavaScript?
parseInt(-0, 10) // 0
parseInt('-0', 10) // -0
Is there a specific rationale behind this inconsistency or is it simply a quirky feature of JavaScript?
parseInt() is designed to function on strings. When applied to a number, it will convert the number to a string.
The result of (-0).toString() is actually 0.
According to the guidelines set in the parseInt function, the initial parameter is transformed into a string, as outlined in the ECMA 5.1 Specification for parseInt,
1. Convert the input to a string with the function ToString(string).
In addition, the ToString function will always return the string '0', even if the input is +0 or -0,
2. If the value is +0 or −0, the result will be the string "0".
This explains why the behavior you are experiencing is occurring.
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