Input only the necessary numeral

Question

Input only the necessary numeral

As someone who is just beginning to learn javascript, I am tasked with creating an input field that allows for the input of 'AND', 123, or ().

I attempted using RegExp to achieve this.

function requiredletter(inputtxt) { 
    var letters =/\a+\n+\d/;
    if(inputtxt.value.match(letters)) {
      alert('Your name has been accepted. You can now try another.');
      return true;
    } else {
      alert('Please only input alphabet characters.');
      return false;
   }
}

Unfortunately, the code is not producing the desired outcome.

javascript regex

Answer 1

Answer №1

I'm completely lost at this point. Here is a string in its entirety.

let regex = /^[a-c]{3}[1-3]{3}[\)\(]{2}$/;

console.log(regex.test('abc123)(')) // true
console.log(regex.test('abc123()')) // true
console.log(regex.test('bca123()')) // true
console.log(regex.test('acb231)(')) // true
console.log(regex.test('bac213()')) // true
console.log(regex.test('cab321)(')) // true
console.log(regex.test('abcd123()')) // false

Answer 2

I'm completely lost at this point. Here is a string in its entirety.

let regex = /^[a-c]{3}[1-3]{3}[\)\(]{2}$/;

console.log(regex.test('abc123)(')) // true
console.log(regex.test('abc123()')) // true
console.log(regex.test('bca123()')) // true
console.log(regex.test('acb231)(')) // true
console.log(regex.test('bac213()')) // true
console.log(regex.test('cab321)(')) // true
console.log(regex.test('abcd123()')) // false

Answer 3

Answer №2

Here is a regular expression that you can use:

pattern = /^[a-c]{3}[1-3]{3}[()]{2}$/;

const display = item => console.log(item);

const check = input => pattern.test(input);

display(check('abc123()')); // true
display(check('bca132)(')); // true
display(check('abce123()')); // false
display(check('abc1234()')); // false
display(check('abc123)(')); // true
display(check('abc123(')); // false

If the input satisfies the conditions specified in the regular expression, it will return true; otherwise, it will return false.

Answer 4

Here is a regular expression that you can use:

pattern = /^[a-c]{3}[1-3]{3}[()]{2}$/;

const display = item => console.log(item);

const check = input => pattern.test(input);

display(check('abc123()')); // true
display(check('bca132)(')); // true
display(check('abce123()')); // false
display(check('abc1234()')); // false
display(check('abc123)(')); // true
display(check('abc123(')); // false

If the input satisfies the conditions specified in the regular expression, it will return true; otherwise, it will return false.

Answer 5

Answer №3

After reviewing the comment provided by the OP, it seems that they are looking to accept a specific set of characters as input. The requirement includes permutations of characters from the string abc123(), allowing any combination of these characters without repetitions. This means that inputs like "abc", "bca", "123()", "(", ")", ")(" are all acceptable.

While a regex solution may not be suitable for this case due to the need to track used characters, a custom function can be utilized. The function outlined below checks whether the input string contains characters solely from the set "abc123()" without any repeats:

function checkString(str){
      main_str = "abc123()";
    
      for (var i = 0; i<str.length; i++){
        chr = str[i];
        chr1 = chr; //make a copy of character
        if (chr == "(" ||  chr== ")") chr1 = "\\" + chr;
        if (main_str == "") return false;
        if (main_str.match(chr1)) main_str = main_str.replace(chr,''); //remove that character from main_str
        else return false;
      }
      return true;
    
    }
 
//Examples of Acceptable Inputs
console.log(checkString("abc123()"));
console.log(checkString("abc"));
console.log(checkString("bca)("));
console.log(checkString("()"));
console.log(checkString("213"));
console.log(checkString("ab12)"));

//Examples of Unacceptable Inputs
console.log(checkString("abc123()a"));
console.log(checkString("abc123()()"));
console.log(checkString("abcd123()"));

The function validates whether the input string meets the criteria specified by the OP, ensuring no character is repeated and all characters are from the set "abc123()". As a result, inputs like abc, a, abc123() will be accepted, while abcd, aa, abc1233 will be rejected.

I trust this explanation addresses your query effectively.

Answer 6

After reviewing the comment provided by the OP, it seems that they are looking to accept a specific set of characters as input. The requirement includes permutations of characters from the string abc123(), allowing any combination of these characters without repetitions. This means that inputs like "abc", "bca", "123()", "(", ")", ")(" are all acceptable.

While a regex solution may not be suitable for this case due to the need to track used characters, a custom function can be utilized. The function outlined below checks whether the input string contains characters solely from the set "abc123()" without any repeats:

function checkString(str){
      main_str = "abc123()";
    
      for (var i = 0; i<str.length; i++){
        chr = str[i];
        chr1 = chr; //make a copy of character
        if (chr == "(" ||  chr== ")") chr1 = "\\" + chr;
        if (main_str == "") return false;
        if (main_str.match(chr1)) main_str = main_str.replace(chr,''); //remove that character from main_str
        else return false;
      }
      return true;
    
    }
 
//Examples of Acceptable Inputs
console.log(checkString("abc123()"));
console.log(checkString("abc"));
console.log(checkString("bca)("));
console.log(checkString("()"));
console.log(checkString("213"));
console.log(checkString("ab12)"));

//Examples of Unacceptable Inputs
console.log(checkString("abc123()a"));
console.log(checkString("abc123()()"));
console.log(checkString("abcd123()"));

The function validates whether the input string meets the criteria specified by the OP, ensuring no character is repeated and all characters are from the set "abc123()". As a result, inputs like abc, a, abc123() will be accepted, while abcd, aa, abc1233 will be rejected.

I trust this explanation addresses your query effectively.

Answer 7

Answer №4

const pattern = /^(ABC|123|\(\))$/;

pattern.test('ABC'); // returns true
pattern.test('123'); // returns true
pattern.test(123);   // returns true
pattern.test('()');  // returns true

pattern.test('abc'); // returns false
pattern.test(213);   // returns false
pattern.test(')(');  // returns false

Answer 8

const pattern = /^(ABC|123|\(\))$/;

pattern.test('ABC'); // returns true
pattern.test('123'); // returns true
pattern.test(123);   // returns true
pattern.test('()');  // returns true

pattern.test('abc'); // returns false
pattern.test(213);   // returns false
pattern.test(')(');  // returns false

Answer 9

Answer №5

If you are looking for all the different combinations of letters from abc, 123, and (), but you do not want them to be grouped together, you can utilize the following regular expression:

var reg = /[abc]{3}|[123]{3}|[()]{2}/;
//This will match aaa, abc, bbb, bca, ccc, 123, 213, (), )( , etc...

https://regex101.com/r/44YoW8/2

Based on the OP's comment in @Kobe's answer, they want any combination of abc, 123, and (). If you only want to allow these specific characters (a, b, c, 1, 2, 3, (, and )) with any quantity of them, you can use the following regex:

/[abc123()]*/

To check if a given string matches the regex pattern:

To test this, you can compare the returned value from the match function with the actual string. Here is an example:

test1 = "abcd";
test2 = "abc";
reg = /abc/;
if (test1 == test1.match(reg)) console.log("test1 matched"); //This will not be printed as it does not match completely

if (test2 == test2.match(reg)) console.log("test2 matched"); //This will be printed

However, if you want permutations of these letters, numbers, and symbols without changing the quantity of each, regex may not be the best solution. You can refer to Regex permutations without repetition. Alternatively, you can easily create a simple function to handle this kind of checking.

Answer 10

If you are looking for all the different combinations of letters from abc, 123, and (), but you do not want them to be grouped together, you can utilize the following regular expression:

var reg = /[abc]{3}|[123]{3}|[()]{2}/;
//This will match aaa, abc, bbb, bca, ccc, 123, 213, (), )( , etc...

https://regex101.com/r/44YoW8/2

Based on the OP's comment in @Kobe's answer, they want any combination of abc, 123, and (). If you only want to allow these specific characters (a, b, c, 1, 2, 3, (, and )) with any quantity of them, you can use the following regex:

/[abc123()]*/

To check if a given string matches the regex pattern:

To test this, you can compare the returned value from the match function with the actual string. Here is an example:

test1 = "abcd";
test2 = "abc";
reg = /abc/;
if (test1 == test1.match(reg)) console.log("test1 matched"); //This will not be printed as it does not match completely

if (test2 == test2.match(reg)) console.log("test2 matched"); //This will be printed

However, if you want permutations of these letters, numbers, and symbols without changing the quantity of each, regex may not be the best solution. You can refer to Regex permutations without repetition. Alternatively, you can easily create a simple function to handle this kind of checking.

Input only the necessary numeral

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

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