Ensuring the timely execution of Javascript functions with Selenium before moving on

While working on creating test cases using Selenium, I encountered an issue.

In one of my test cases, there is a small form and a search button on the website I'm testing. Filling the form and clicking the button are not the problem. The issue arises after clicking the button.

Upon clicking the button, the following function is triggered:

function showLoading(){
document.getElementById("loadingDiv").style.display = "";
}

This function essentially displays a DIV that contains a "loading" image to prevent visitors from seeing the content loading via AJAX.

Once the content is loaded, the following function is called:

function hideLoading(){
document.getElementById("loadingDiv").style.display = "none";
}

This function hides the "loading" DIV so the visitor can view the results.

Since the loading time may vary and SLEEPs cannot be used due to the need for real execution time, is there a way (using Java - JUnit4) to make Selenium wait until the second function is executed before proceeding with the next steps?

EDIT: I am using Selenium RC. To initiate the driver, I use:

public void setUp() throws Exception {
        selenium = new DefaultSelenium("localhost", 4444, "*iexplore", "website-url");
        selenium.start();
    }

Ultimately, the solution provided by Pavel Janicek worked perfectly for me:

boolean proceed = true;
      int i = 0;
      while (proceed){      
      i= i+200;
      Thread.sleep(1000);
      if (i>30000){
        proceed = false;
      }
      if (!selenium.isVisible("id=loadingDiv")){
         proceed = false;
      }      
      if (selenium.isVisible("id=loadingDiv")){
             proceed = true;
          }      
     }

Answer №1

For waiting conditions in Selenium, you can utilize the waitForCodition
When working with WebDriver, options like WebDriverBackedSelenium or FluentWait can be considered.
Check out this resource for more information.

Answer №2

If you're looking to optimize your waiting time in Selenium automation, consider using FluentWait. This method allows you to specify a timeout and condition for waiting until a certain Boolean value is true. By utilizing FluentWait, the process will only check every 1 second if the desired element is visible, instead of continuously checking at a faster rate.

public static void customWait(WebDriver driver, int timeout, final By locator){
    FluentWait<WebDriver> wait = new FluentWait<WebDriver>(driver)
       .withTimeout(timeout, TimeUnit.SECONDS)
       .pollingEvery(1, TimeUnit.SECONDS)
       .ignoring(NoSuchElementException.class)

    wait.until(new Function<WebDriver, Boolean>() {
        public Boolean apply(WebDriver driver) {
            WebElement element = driver.findElement(locator);
            return !element.isDisplayed();
        }
    });
}

For those using Selenium 1 and wanting to transition to Selenium 2, make sure to obtain the wrapped driver correctly:

Selenium selenium = new DefaultSelenium("localhost", 4444, "*iexplore", "website-url");
CommandExecutor executor = new SeleneseCommandExecutor(selenium); 
WebDriver driver = new RemoteWebDriver(executor, new DesiredCapabilities());

Answer №3

** UPDATE 3**

Here's the current code:

DefaultSelenium selenium = new DefaultSelenium("localhost",4444,"*iexplore", "websiteURL");

You can still utilize the isVisible command in this way:

boolean doTheLoop = true;
    int i = 0;
    while (doTheLoop){      
        i = i+200;
        Thread.sleep(200);
        if (i>30000){
            doTheLoop = false;
        }
        if (!selenium.isVisible("id=the ID Of element")){
            doTheLoop = false;
      }      
}

Make sure to avoid getting stuck in an infinite loop.

I have no experience with DefaultSelenium, so please use the isVisible() function just like you would use click(), for instance.

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