Increase the value of X within the given string

Question

Increase the value of X within the given string

I am working on developing an application that transforms the initial string:

1.2.3.X

Into multiple strings:

1.2.3.0

1.2.3.1

1.2.3.2

1.2.3.3

1.2.3.4

......

This is a snippet of the code I have written so far:

String.prototype.count=function(c) { 
  var result = 0, i = 0;
  for(i;i<this.length;i++)if(this[i]==c)result++;
  return result;
};
var x = ["","","","","","","","","","","","","","","",""]
var brutenumber = ""
var ip = "1.2.X.X"
if (ip.count(".") >= 4) {
 console.log("Non valid IP Input"); 
} 
else { 
  numberX = ip.count("X");
  if (numberX < 1) {
   console.log("No X given.") 
  }
  else if (numberX > 12)  {
    console.log("Too many X given! Result can't be an IP")
  } 
  else {
    for (i = 1;i <= numberX ; i++ ) {
      brutenumber = brutenumber + "9";
      
    }
  }
  
for (d = 0;d <= brutenumber; d++) {
  var lastchar = d.toString().slice(-1);
  console.log(lastchar)

}
}

My application successfully calculates the number of attempts required to cover all possibilities, but now I am facing a challenge:

for (d = 0 ;d <= brutenumber; d++) {

The issue is that the numbers generated are in the format 0, 1, 10, 11, 12 instead of 001, 002, 003... I need to adjust the code to achieve this. Additionally, I am struggling with inserting values for the X in the search string like 1.2.3.X. I am open to any suggestions or solutions for this task, as the searchString can vary in format. Thank you for your help!

Thanks

javascript arrays

Answer 1

Answer №1

After carefully analyzing the problem, I have devised a solution that can be implemented in the following manner:

function ipListGenerator(s){
  var nos = Array(256).fill().map((_,i) => "0".repeat(2 - ~~Math.log10(i))+i);
  return nos.map(no => s.replace(/x/i,no));
}

var ipList = ipListGenerator("1.2.3.X");
console.log(ipList)

.as-console-wrapper { max-height: 100% !important; top: 0; }

Alternatively, the code can be further simplified by merging the two .map() functions into one, like this:

function ipListGenerator(s){
  return Array(256).fill().map((_,i) => s.replace(/x/i, "0".repeat(2 - ~~Math.log10(i))+i));
}

As indicated in your comment, this simplification of the code is quite significant.

function ipListGenerator(s){
  return Array(10).fill().map((_,i) => s.replace(/x/i, i));
}

console.log(ipListGenerator("1.2.3.x"));

.as-console-wrapper { max-height: 100% !important; top: 0; }

Expanding on the above code, it is possible to have multiple x values ranging from 0 to 9. However, it should be noted that handling a high number of x values can result in a time-consuming process due to the combinatorial nature of the task. It is advisable to avoid applying this code to strings with more than 5 xs.

function fillxs(s){
  function runner(s){
    return Array(10).fill().map((_,i) => s.replace(/x/i, i));
  }
  var xc = s.match(/x/ig).length;
  result = [s];
  while (xc--) result = result.reduce((r,s) => r.concat(runner(s)),[])
  return result;
}

var nox = [];
console.time("test");
nox = fillxs("1.1.1x3.x1x");
console.timeEnd("test");
console.log(nox);

Answer 2

After carefully analyzing the problem, I have devised a solution that can be implemented in the following manner:

function ipListGenerator(s){
  var nos = Array(256).fill().map((_,i) => "0".repeat(2 - ~~Math.log10(i))+i);
  return nos.map(no => s.replace(/x/i,no));
}

var ipList = ipListGenerator("1.2.3.X");
console.log(ipList)

.as-console-wrapper { max-height: 100% !important; top: 0; }

Alternatively, the code can be further simplified by merging the two .map() functions into one, like this:

function ipListGenerator(s){
  return Array(256).fill().map((_,i) => s.replace(/x/i, "0".repeat(2 - ~~Math.log10(i))+i));
}

As indicated in your comment, this simplification of the code is quite significant.

function ipListGenerator(s){
  return Array(10).fill().map((_,i) => s.replace(/x/i, i));
}

console.log(ipListGenerator("1.2.3.x"));

.as-console-wrapper { max-height: 100% !important; top: 0; }

Expanding on the above code, it is possible to have multiple x values ranging from 0 to 9. However, it should be noted that handling a high number of x values can result in a time-consuming process due to the combinatorial nature of the task. It is advisable to avoid applying this code to strings with more than 5 xs.

function fillxs(s){
  function runner(s){
    return Array(10).fill().map((_,i) => s.replace(/x/i, i));
  }
  var xc = s.match(/x/ig).length;
  result = [s];
  while (xc--) result = result.reduce((r,s) => r.concat(runner(s)),[])
  return result;
}

var nox = [];
console.time("test");
nox = fillxs("1.1.1x3.x1x");
console.timeEnd("test");
console.log(nox);

Increase the value of X within the given string

Answer №1

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