Discover a corresponding object within an array

Question

Discover a corresponding object within an array

I am currently dealing with an array of objects in Javascript where I need to verify if a certain value exists within any object and return the corresponding id. The issue arises when using the some() function as it only seems to match the first object.

The array in question is structured as follows:

const testObj = [
  {id: 1, nombre: "Juan"},
  {id: 2, nombre: "María"},
  {id: 3, nombre: "Pedro"}
];

This is my current approach:

let test = 'María'

let priority;

testObj.some(item => item.nombre === test ? priority = item.id : priority = 7)

However, upon checking the result, it yields:

console.log(priority) // 7

I'm puzzled as to why it fails to return the accurate id when the specified value does exist within one of the objects. Any insights on this behavior?

javascript arrays json

Answer 1

Answer №1

The method Array.some() will stop as soon as the callback function returns a truthy value, such as true. In this case, the some ends when the priortiy is set to 7 due to its truthy nature. The purpose of Array.some() is to determine if at least one item meets certain criteria, with the result being a Boolean value (true if at least one matches, false if none). It's not intended for simple looping or finding a specific item.

Instead, consider using Array.find(). If the item is located, destructure its id and assign it to priority. When Array.find() fails to find an item, it will return null. To address this scenario, utilize the Nullish coalescing operator (??) to provide a fallback object with a default value of 7.

const testObj = [
  {id: 1, nombre: "Juan"},
  {id: 2, nombre: "María"},
  {id: 3, nombre: "Pedro"}
];

const test = 'María'

// utilizing destructuring
const { id: priority } = testObj.find(o => o.nombre === test) ?? { id: 7 }
console.log(priority)

// using a ternary operation
const item = testObj.find(o => o.nombre === test)
const priority2 = item ? item.id : 7
console.log(priority2)

// employing optional chaining
const priority3 = testObj.find(o => o.nombre === test)?.id ?? 7;
console.log(priority3)

Answer 2

The method Array.some() will stop as soon as the callback function returns a truthy value, such as true. In this case, the some ends when the priortiy is set to 7 due to its truthy nature. The purpose of Array.some() is to determine if at least one item meets certain criteria, with the result being a Boolean value (true if at least one matches, false if none). It's not intended for simple looping or finding a specific item.

Instead, consider using Array.find(). If the item is located, destructure its id and assign it to priority. When Array.find() fails to find an item, it will return null. To address this scenario, utilize the Nullish coalescing operator (??) to provide a fallback object with a default value of 7.

const testObj = [
  {id: 1, nombre: "Juan"},
  {id: 2, nombre: "María"},
  {id: 3, nombre: "Pedro"}
];

const test = 'María'

// utilizing destructuring
const { id: priority } = testObj.find(o => o.nombre === test) ?? { id: 7 }
console.log(priority)

// using a ternary operation
const item = testObj.find(o => o.nombre === test)
const priority2 = item ? item.id : 7
console.log(priority2)

// employing optional chaining
const priority3 = testObj.find(o => o.nombre === test)?.id ?? 7;
console.log(priority3)

Answer 3

Answer №2

The Challenge

An issue arises when you set the priority value to 7 in the else condition of the ternary operator, as it will always execute regardless of whether the value is found or not.

The Resolution:

To address this, adjust your code so that the priority value is only set when the desired value is found within the array.

let test = 'María';
let priority = null;
const testObj = [ {id: 1, nombre: "Juan"}, {id: 2, nombre: "María"}, {id: 3, nombre: "Pedro"} ];

testObj.some(item => {
  if (item.nombre === test) {
    priority = item.id;
    return true;
  }
});

console.log(priority); // 2

Utilizing `for..of` Loop:

let test = 'María';
let priority = 7;

for (const item of testObj) {
  if (item.nombre === test) {
    priority = item.id;
    break;
  }
}

console.log(priority); // 2

Implementing `find()` Method:

let test = 'María';
let priority = testObj.find(item => item.nombre === test)?.id || 7;

console.log(priority); // 2

Note : Utilizing find() or a straightforward for..of loop with an early break statement may be more effective than using some.

Answer 4

The Challenge

An issue arises when you set the priority value to 7 in the else condition of the ternary operator, as it will always execute regardless of whether the value is found or not.

The Resolution:

To address this, adjust your code so that the priority value is only set when the desired value is found within the array.

let test = 'María';
let priority = null;
const testObj = [ {id: 1, nombre: "Juan"}, {id: 2, nombre: "María"}, {id: 3, nombre: "Pedro"} ];

testObj.some(item => {
  if (item.nombre === test) {
    priority = item.id;
    return true;
  }
});

console.log(priority); // 2

Utilizing `for..of` Loop:

let test = 'María';
let priority = 7;

for (const item of testObj) {
  if (item.nombre === test) {
    priority = item.id;
    break;
  }
}

console.log(priority); // 2

Implementing `find()` Method:

let test = 'María';
let priority = testObj.find(item => item.nombre === test)?.id || 7;

console.log(priority); // 2

Note : Utilizing find() or a straightforward for..of loop with an early break statement may be more effective than using some.

Discover a corresponding object within an array

Answer №1

Answer №2

The Challenge

The Resolution:

Utilizing `for..of` Loop:

Implementing `find()` Method:

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Discover a corresponding object within an array

Answer №1

Answer №2

The Challenge

The Resolution:

Utilizing for..of Loop:

Implementing find() Method:

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Utilizing `for..of` Loop:

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