I am working with an array in JavaScript. When the name value is empty, I want to move it to the end of the array. How can I achieve this?
Example:
const data : [
{
id:0,
name:"gorkem"
}
{
id:1,
name:""
}
{
id:2,
name:"ahmet"
}
];
After Replacement:
const data : [
{
id:0,
name:"gorkem"
}
{
id:2,
name:"ahmet"
}
{
id:1,
name:""
}
];
To separate the items based on whether their names are empty or not, utilize two filter calls - one to extract non-empty names and the other for empty names. Finally, merge these two arrays together.
const nonEmptyNames = data.filter(item => item.name);
const emptyNames = data.filter(item => !item.name);
const mergedArray = nonEmptyNames.concat(emptyNames);
To achieve a reversed sort order based on the truthiness of the "name" property, you can simply sort the array accordingly.
const data = [{
id: 0,
name: "John"
}, {
id: 1,
name: ""
}, {
id: 2,
name: "Alice"
}];
console.log(data.sort((a,b) => !a.name - !b.name));
In this code snippet, we are leveraging the fact that an empty string is evaluated as falsy (equivalent to 0), while a non-empty string is considered truthy (equivalent to 1). By negating these values with '!', we can achieve the desired reverse sorting order and treat them as booleans.
Result:
[
{
"id": 0,
"name": "John"
},
{
"id": 2,
"name": "Alice"
},
{
"id": 1,
"name": ""
}
]
To begin, ensure you have a valid array:
const information = [{
id:0,
name:"John"
}, {
id:1,
name:""
}, {
id:2,
name:"Anna"
}];
With that in place, you can utilize a loop to eliminate any empty name entries and move them to the end of the array:
for (let index = 0; index < information.length; index++) {
if (information[index].name === '') {
let value = information[index];
information.splice(index, 1);
information.push(value);
}
}
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