Why am I not getting the minimum value when it displays 0, but Math.max() correctly shows the maximum value?
function findMin(ar) {
var min_val = 0;
for(var i = 0; i < ar.length; i++) {
min_val = Math.min(min_val,ar[i]);
}
document.write(min_val);
}
findMin([14,99, 10, 18,19, 11, 34]);
When comparing the variable to `min_val`, it consistently returns 0. This is due to the fact that in an array, 0 is lower than any other value present. Therefore, `min_val` will always remain as 0 since it cannot find a lower value within the array.
As a solution, I propose the following code:
let ar =[14,99,10,18,19,11,34]
let min_val = Math.min(...ar)
console.log(min_val)This approach is also more concise compared to using a for-loop.
To achieve the desired outcome, you should begin by setting the minimum value to an extremely large number (Infinity).
var min_value = Infinity;
for(var i = 0; i < arr.length; i++) {
min_value = Math.min(min_value, arr[i]);
}
document.write(min_value);
}
values([14,99, 10, 18,19, 11, 34]);This script will output Infinity if the array is empty, or the smallest value within the given input.
Math.min() can accept arguments like Math.min(-2, -3, -1) or with an array like Math.min(...arr). In this case, you are passing the arguments as
Math.min([14,99, 10, 18,19, 11, 34], 0)Math.min() already finds the minimum value, there's no need for a loop. The solution can be written as:
function values(ar) {
var min_val = Math.min(...ar);
//document.write(min_val);
return min_val
}
console.log(values([14,99, 10, 18,19, 11, 34]))Alternatively (to match your specific case):
function values(ar) {
var min_val = Math.min(...ar);
document.write(min_val);
}
In its shortest form:
document.write(Math.min(...ar));
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