Guide to incorporating a tally system into a collection of similar items

Hey everyone, I'm working on creating a function that counts the number of identical elements in an array. If the next element is greater than the previous one, 1 is added to the counter. However, I am facing an issue when all elements are identical. In this case, I want the function to add 1 to the counter for each identical element. For example, with [4,4,4,4,4], the output should be 5 since there are 5 identical elements.

function countIdentical(arr) {
  let counter = 0;
  let counterIdentical = 0;

  for (let i = 0; i < arr.length; i++) {
    if (arr[i] < arr[(i + 1) % arr.length]) {
      counter++;
    }
  }
  return counter;
}
console.log(countIdentical([4, 3, 3, 2, 1, 2, 2, 1, 1, 3])); //expected output 3
console.log(countIdentical([
  [4, 4, 4, 4, 4]
])); //expected output 5

Answer №1

It seems like your second array was nested within another array

Allow me to propose a solution:

function findTowerHeight(arr) {
  if (arr.every(val => val === arr[0])) return arr.length
  return arr.filter((val,i) => i === 0 || i > 0 && val > arr[i-1]).length 
  
}
console.log(findTowerHeight([4, 3, 3, 2, 1, 2, 2, 1, 1, 3])) //expected output 3
console.log(findTowerHeight([ 4, 4, 4, 4, 4 ])) //expected output 5

Answer №2

function countIncreasingValues(arr) {
  let counter = 0;
  let identicalCount = 0;
  
  for (let i = 1; i <= arr.length; i++) {
    if (arr[i] >= arr[(i - 1)]) {
      counter++;
    }
  }
  
  return counter;
}

This function counts the number of increasing values in an array.

  1. Start iterating from the second item to the last item in the array
  2. Compare each element with the previous one to check if it is greater or equal
  3. If the comparison is true, increment the counter

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