finding the ip address of the current device using javascript

Question

finding the ip address of the current device using javascript

While attempting to retrieve the IP address of my machine using JavaScript with Request.UserHostAddress, I am encountering an issue where instead of receiving the IP address, I am getting 'undefined'.

Here is my code:

var ip = Request.UserHostAddress;
console.log(ip);

javascript websocket

Answer 1

Answer №1

Here is a code snippet for retrieving the IP address:

<!DOCTYPE html>
<html>
<head>
<script class="jsbin" src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.4/jquery.min.js"></script>

</head>
<body>
 Ip Address:=<h3 class='ipAdd'><h3>
  </body>

<script>
$(document).ready(function getIP()
{
  window.RTCPeerConnection = window.RTCPeerConnection || window.mozRTCPeerConnection || window.webkitRTCPeerConnection;  
var pc = new RTCPeerConnection({iceServers:[]}), 
noop = function(){}; 
     
   pc.createDataChannel("");  
pc.createOffer(pc.setLocalDescription.bind(pc), noop);   
    pc.onicecandidate = function(ice){ 
   if(!ice || !ice.candidate || !ice.candidate.candidate)  return;

        var myIP = /([0-9]{1,3}(\.[0-9]{1,3}){3}|[a-f0-9]{1,4}(:[a-f0-9]{1,4}){7})/.exec(ice.candidate.candidate)[1];

        console.log('my IP: ', myIP); 
$('.ipAdd').text(myIP);
  
        pc.onicecandidate = noop;
  
 }; 
});
      
</script>
</html>

Answer 2

Here is a code snippet for retrieving the IP address:

<!DOCTYPE html>
<html>
<head>
<script class="jsbin" src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.4/jquery.min.js"></script>

</head>
<body>
 Ip Address:=<h3 class='ipAdd'><h3>
  </body>

<script>
$(document).ready(function getIP()
{
  window.RTCPeerConnection = window.RTCPeerConnection || window.mozRTCPeerConnection || window.webkitRTCPeerConnection;  
var pc = new RTCPeerConnection({iceServers:[]}), 
noop = function(){}; 
     
   pc.createDataChannel("");  
pc.createOffer(pc.setLocalDescription.bind(pc), noop);   
    pc.onicecandidate = function(ice){ 
   if(!ice || !ice.candidate || !ice.candidate.candidate)  return;

        var myIP = /([0-9]{1,3}(\.[0-9]{1,3}){3}|[a-f0-9]{1,4}(:[a-f0-9]{1,4}){7})/.exec(ice.candidate.candidate)[1];

        console.log('my IP: ', myIP); 
$('.ipAdd').text(myIP);
  
        pc.onicecandidate = noop;
  
 }; 
});
      
</script>
</html>

Answer 3

Answer №2

To retrieve your IP address, you can utilize an ajax call to hostip.info or a similar service.

function getIPAddress() {
        if (window.XMLHttpRequest) {
            xmlhttp = new XMLHttpRequest();
        } else {
            xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
        }

        xmlhttp.open("GET", "http://api.hostip.info/get_html.php", false);
        xmlhttp.send();

        var hostipInfo = xmlhttp.responseText.split("\n");

        for (var i = 0; i < hostipInfo.length; i++) {
            var ipAddress = hostipInfo[i].split(":");
            if (ipAddress[0] === "IP") {
                return ipAddress[1];
            }
        }

        return false;
    }

Answer 4

To retrieve your IP address, you can utilize an ajax call to hostip.info or a similar service.

function getIPAddress() {
        if (window.XMLHttpRequest) {
            xmlhttp = new XMLHttpRequest();
        } else {
            xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
        }

        xmlhttp.open("GET", "http://api.hostip.info/get_html.php", false);
        xmlhttp.send();

        var hostipInfo = xmlhttp.responseText.split("\n");

        for (var i = 0; i < hostipInfo.length; i++) {
            var ipAddress = hostipInfo[i].split(":");
            if (ipAddress[0] === "IP") {
                return ipAddress[1];
            }
        }

        return false;
    }

Answer 5

Answer №3

This is my revised version of the solution. I have eliminated the need for jQuery, encapsulated the functionality within a function, and incorporated some ES6 features.

<html>
<head><title>Find My IP Address</title></head>
<body><h3 class='ipAdd'>My IP Address : <h3></body>

<script> "use strict";
  window.RTCPeerConnection = window.RTCPeerConnection ||
                             window.mozRTCPeerConnection ||
                             window.webkitRTCPeerConnection;  

  function getIPAddress (callback) {
    // Calls the callback function with the local host IP address found 
    // using RTC functions. We cannot simply return the IP address 
    // because the RTC functions are asynchronous.

    var pc = new RTCPeerConnection ({iceServers: []}),
        noop = () => {};

    pc.onicecandidate = ice => 
      callback = callback ((ice = ice && ice.candidate && ice.candidate.candidate)
                   ? ice.match (/(\d{1,3}(\.\d{1,3}){3}|[a-f\d]{1,4}(:[a-f\d]{1,4}){7})/)[1]
                   : 'unavailable') || noop;
    pc.createDataChannel ("");  
    pc.createOffer (pc.setLocalDescription.bind (pc), noop);
  };

  getIPAddress (address => { document.querySelector ('.ipAdd').innerHTML += address; });
</script>

</html>

Answer 6

This is my revised version of the solution. I have eliminated the need for jQuery, encapsulated the functionality within a function, and incorporated some ES6 features.

<html>
<head><title>Find My IP Address</title></head>
<body><h3 class='ipAdd'>My IP Address : <h3></body>

<script> "use strict";
  window.RTCPeerConnection = window.RTCPeerConnection ||
                             window.mozRTCPeerConnection ||
                             window.webkitRTCPeerConnection;  

  function getIPAddress (callback) {
    // Calls the callback function with the local host IP address found 
    // using RTC functions. We cannot simply return the IP address 
    // because the RTC functions are asynchronous.

    var pc = new RTCPeerConnection ({iceServers: []}),
        noop = () => {};

    pc.onicecandidate = ice => 
      callback = callback ((ice = ice && ice.candidate && ice.candidate.candidate)
                   ? ice.match (/(\d{1,3}(\.\d{1,3}){3}|[a-f\d]{1,4}(:[a-f\d]{1,4}){7})/)[1]
                   : 'unavailable') || noop;
    pc.createDataChannel ("");  
    pc.createOffer (pc.setLocalDescription.bind (pc), noop);
  };

  getIPAddress (address => { document.querySelector ('.ipAdd').innerHTML += address; });
</script>

</html>

Answer 7

Answer №4

<!DOCTYPE html>
<html>
<head>
<script class="jsbin" src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.4/jquery.min.js"></script>

</head>
<body>
 Ip Address:=<h3 class='ipAdd'><h3>
  </body>

<script>
$(document).ready(function xyz()
{
  window.RTCPeerConnection = window.RTCPeerConnection || window.mozRTCPeerConnection || window.webkitRTCPeerConnection;  
var pc = new RTCPeerConnection({iceServers:[]}), 
noop = function(){}; 
     
   pc.createDataChannel("");  
pc.createOffer(pc.setLocalDescription.bind(pc), noop);   
    pc.onicecandidate = function(ice){ 
   if(!ice || !ice.candidate || !ice.candidate.candidate)  return;

        var myIP = /([0-9]{1,3}(\.[0-9]{1,3}){3}|[a-f0-9]{1,4}(:[a-f0-9]{1,4}){7})/.exec(ice.candidate.candidate)[1];

        console.log('my IP: ', myIP); 
$('.ipAdd').text(myIP);
  
        pc.onicecandidate = noop;
  
 }; 
});
      
</script>
</html>

Answer 8

<!DOCTYPE html>
<html>
<head>
<script class="jsbin" src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.4/jquery.min.js"></script>

</head>
<body>
 Ip Address:=<h3 class='ipAdd'><h3>
  </body>

<script>
$(document).ready(function xyz()
{
  window.RTCPeerConnection = window.RTCPeerConnection || window.mozRTCPeerConnection || window.webkitRTCPeerConnection;  
var pc = new RTCPeerConnection({iceServers:[]}), 
noop = function(){}; 
     
   pc.createDataChannel("");  
pc.createOffer(pc.setLocalDescription.bind(pc), noop);   
    pc.onicecandidate = function(ice){ 
   if(!ice || !ice.candidate || !ice.candidate.candidate)  return;

        var myIP = /([0-9]{1,3}(\.[0-9]{1,3}){3}|[a-f0-9]{1,4}(:[a-f0-9]{1,4}){7})/.exec(ice.candidate.candidate)[1];

        console.log('my IP: ', myIP); 
$('.ipAdd').text(myIP);
  
        pc.onicecandidate = noop;
  
 }; 
});
      
</script>
</html>

finding the ip address of the current device using javascript

Answer №1

Answer №2

Answer №3

Answer №4

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