Finding a quicker route to fulfill a commitment

When dealing with asynchronous behavior in a function, I often find myself creating a deferred and returning a promise. For example:

var deferred = $q.defer();
//...some async operation
return deferred.promise;

However, sometimes I want to skip the async activity and immediately return a resolved promise. Is there a more efficient way to achieve this?

For instance, would it be appropriate to use the following shortcut at the beginning of my function:

if (shouldShortcut) {
    return $q.when(true);
}

Answer №1

You have the option to simply fulfill the deferred right away, while also returning its promise:

if (shouldTakeShortcut) {
  deferred.fulfill();
  return deferred.promise;
}

Answer №2

Update: Upon further review, it seems that the discussion is centered around $q and not Q. Refer to the following for my initial response regarding the Q library.

According to Benjamin Gruenbaum's now-deleted comment below, using $q.when() is a suitable approach:

var resolvedPromise = $q.when();

If you need to resolve with a specific value, simply include it as an argument in when():

var resolvedPromise = $q.when("all good");

There is no necessity to utilize deferreds in this scenario. It is recommended to minimize the use of deferreds, as they are likely to become outdated in favor of the revealing constructor pattern featured in ES6.


(previous response)

The Q library offers a method that aligns with the ES6 promises standard for achieving this task:

Q.Promise.resolve();

This function generates a resolved promise.

To resolve it with a specific value, you can pass that value as a parameter:

Q.Promise.resolve("all good");  // promise resolved with the value "all good"

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