In order to achieve a smooth camera movement in three.js, it is essential to compute the position of point C. This calculation will ensure that the camera can smoothly transition from point A to a specific distance away at point B.
In order to achieve a smooth camera movement in three.js, it is essential to compute the position of point C. This calculation will ensure that the camera can smoothly transition from point A to a specific distance away at point B.
It is quite simple to achieve this with the help of three.js methods.
If we assume that variables a, b, and c represent instances of THREE.Vector3(),
a.set( 2, 1, 4 );
b.set( 9, 4, 2 );
c.subVectors( a, b ).setLength( dist ).add( b );
This code snippet uses three.js version r.91
If you are looking to determine the coordinates of point C, which is positioned on the line connecting points B and A at a specified distance from B, the process can be accomplished through the following simple steps:
B to point A (essentially, this would be A - B).B.To illustrate this concept, here is a basic example using JavaScript:
const A = [2, 1, 4];
const B = [9, 4, 2];
const dist = 3;
function addVectors(v1, v2) {
return v1.map((x, i) => x + v2[i]);
}
function scalarMultiply(v, c) {
return v.map(x => x*c);
}
function getLength(v) {
return Math.hypot(...v);
}
const vecB2A = addVectors(A, scalarMultiply(B, -1)); // Step 1
const normB2A = scalarMultiply(vecB2A, 1/getLength(vecB2A)); // Step 2
const distB2A = scalarMultiply(normB2A, dist); // Step 3
const C = addVectors(B, distB2A); // Final step
console.log(C);To find point C, simply subtract a certain distance in the direction of vector AB from point B. It's a straightforward process:
Calculate the vector v from A to B as (xB-xA, yB-yA, zB-zA) divided by the distance between A and B.
Next, determine C by subtracting d times v from B, where d represents how far away from B you want C to be located.
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