Filter an array of objects that include a nested array

Question

Filter an array of objects that include a nested array

Currently, I am attempting to implement a nested filter on an array of objects. The challenge lies in applying the filter within the object based on a key that contains another array of objects.

Below is the snippet of code:

const items = [
  { name: "123", id: 1, value:  true, arr: [{ id: 1 }] },
  { name: "456", id: 2, value: false, arr: [{ id: 2 }] },
  { name: "456", id: 2, value: false, arr: [{ id: 3 }] },
  { name: "456", id: 2, value: false, arr: [{ id: 4 }] },
  { name: "456", id: 2, value: false, arr: [{ id: 5 }] },
  { name: "456", id: 2, value: false, arr: [{ id: 6 }] },
];

const newArray = items.filter((objects) => {
  return objects.arr.some((item) => item.id === 2);
});
console.log(newArray);

I am unsure about where to place the return statement as my current implementation seems to only result in an empty array being returned.

javascript arrays object filter javascript-objects

Answer 1

Answer №1

Make sure to validate that the nested array includes the desired id and pass the outcome back to the filter method.

const
    items = [{ name: "123", id: 1, value: true, arr: [{ id: 1 }] }, { name: "456", id: 2, value: false, arr: [{ id: 2 }] }, { name: "456", id: 2, value: false, arr: [{ id: 3 }] }, { name: "456", id: 2, value: false, arr: [{ id: 4 }] }, { name: "456", id: 2, value: false, arr: [{ id: 5 }] }, { name: "456", id: 2, value: false, arr: [{ id: 6 }] }],
    result = items.filter(({ arr }) => arr.some(({ id }) => id === 2));

console.log(result);

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Answer 2

Make sure to validate that the nested array includes the desired id and pass the outcome back to the filter method.

const
    items = [{ name: "123", id: 1, value: true, arr: [{ id: 1 }] }, { name: "456", id: 2, value: false, arr: [{ id: 2 }] }, { name: "456", id: 2, value: false, arr: [{ id: 3 }] }, { name: "456", id: 2, value: false, arr: [{ id: 4 }] }, { name: "456", id: 2, value: false, arr: [{ id: 5 }] }, { name: "456", id: 2, value: false, arr: [{ id: 6 }] }],
    result = items.filter(({ arr }) => arr.some(({ id }) => id === 2));

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 3

Answer №2

Utilize Array#some function to verify if the current array arr contains an element with an id of 2:

const items = [ { name: "123", id: 1, value:  true, arr: [{ id: 1 }] }, { name: "456", id: 2, value: false, arr: [{ id: 2 }] }, { name: "456", id: 2, value: false, arr: [{ id: 3 }] }, { name: "456", id: 2, value: false, arr: [{ id: 4 }] }, { name: "456", id: 2, value: false, arr: [{ id: 5 }] }, { name: "456", id: 2, value: false, arr: [{ id: 6 }] } ];

const newArray = items.filter(({ arr = [] }) => 
  arr.some(({ id }) => id === 2)
);

console.log(newArray);

Answer 4

Utilize Array#some function to verify if the current array arr contains an element with an id of 2:

const items = [ { name: "123", id: 1, value:  true, arr: [{ id: 1 }] }, { name: "456", id: 2, value: false, arr: [{ id: 2 }] }, { name: "456", id: 2, value: false, arr: [{ id: 3 }] }, { name: "456", id: 2, value: false, arr: [{ id: 4 }] }, { name: "456", id: 2, value: false, arr: [{ id: 5 }] }, { name: "456", id: 2, value: false, arr: [{ id: 6 }] } ];

const newArray = items.filter(({ arr = [] }) => 
  arr.some(({ id }) => id === 2)
);

console.log(newArray);

Answer 5

Answer №3

Since there is only one object in the arr array, you can simply access it using the index [0].

Here's a Demo of How It Works:

const items = [
  { name: "123", id: 1, value:  true, arr: [{ id: 1 }] },
  { name: "456", id: 2, value: false, arr: [{ id: 2 }] },
  { name: "456", id: 2, value: false, arr: [{ id: 3 }] },
  { name: "456", id: 2, value: false, arr: [{ id: 4 }] },
  { name: "456", id: 2, value: false, arr: [{ id: 5 }] },
  { name: "456", id: 2, value: false, arr: [{ id: 6 }] },
];

const newArray = items.filter((obj) => {
    if (obj.arr[0].id === 2) {
    return obj;
  }
});

console.log(newArray);

I provided this solution based on the specific issue you are facing. However, if there are multiple objects in your arr array, you might want to consider using the Array.some() method as recommended by other responses.

Answer 6

Since there is only one object in the arr array, you can simply access it using the index [0].

Here's a Demo of How It Works:

const items = [
  { name: "123", id: 1, value:  true, arr: [{ id: 1 }] },
  { name: "456", id: 2, value: false, arr: [{ id: 2 }] },
  { name: "456", id: 2, value: false, arr: [{ id: 3 }] },
  { name: "456", id: 2, value: false, arr: [{ id: 4 }] },
  { name: "456", id: 2, value: false, arr: [{ id: 5 }] },
  { name: "456", id: 2, value: false, arr: [{ id: 6 }] },
];

const newArray = items.filter((obj) => {
    if (obj.arr[0].id === 2) {
    return obj;
  }
});

console.log(newArray);

I provided this solution based on the specific issue you are facing. However, if there are multiple objects in your arr array, you might want to consider using the Array.some() method as recommended by other responses.

Filter an array of objects that include a nested array

Answer №1

Answer №2

Answer №3

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