Exploring the Power of Filtering Arrays in JavaScript

Currently, I am enrolled in online JavaScript courses and I'm intrigued by a particular task:

In this task, we are given an initial array (the first argument in the destroyer function) followed by one or more arguments. The goal is to eliminate all elements from the initial array that share the same value as these arguments.

Below is my initial solution to the task, but unfortunately, it is not working as expected:

 function destroyer(arr) {
   // Separating the array from the numbers meant for filtering; 
   var filterArr = [];
   for (var i = 1; i < arguments.length; i++) {
     filterArr.push(arguments[i]);
   }

   // Console log to verify the correct numbers
   console.log(filterArr);

   // Defining the parameters for the filter function
   function filterIt(value) {
       for (var j = 0; j < filterArr.length; j++) {
         if (value === filterArr[j]) {
           return false;
         }
       }
     }
     // Check the progress made
   return arguments[0].filter(filterIt);
 }

 destroyer([1, 2, 3, 1, 2, 3], 2, 3);

While I did manage to find a solution, it doesn't quite make sense to me. Hence, I'm seeking clarification on why the following code actually works:

function destroyer(arr) {
  // Separating the array from the numbers meant for filtering; 
  var filterArr = [];
  for (var i = 1; i < arguments.length; i++) {
    filterArr.push(arguments[i]);
  }

  // Console log to verify the correct numbers
  console.log(filterArr);

  // Defining the parameters for the filter function
  function filterIt(value) {
      for (var j = 0; j < filterArr.length; j++) {
        if (value === filterArr[j]) {
          return false;
        }
        // The 'true' boolean here is key to the code execution, and I'm struggling to grasp the reason behind it. I would greatly appreciate any insights you can provide.
      }
      return true;
    }
    // Check the progress made
  return arguments[0].filter(filterIt);
}

destroyer([1, 2, 3, 1, 2, 3], 2, 3);

Thank you for any guidance and explanations!

Answer №1

To achieve the same result using a simplified approach, you can leverage the power of Array.prototype.reduce(), either in ES6 or ES5 syntax.

Here is the ES6 version:

var destroyer = (a,...f) => a.reduce((p,c) => f.includes(c) ? p : p.concat(c),[]);
console.log(destroyer([1, 2, 3, 1, 2, 3], 2, 3));

And here is the ES5 version:

function destroyer(a){
  var f = Array.prototype.slice.call(arguments,1);
  return a.reduce(function(p,c){
                    return f.indexOf(c) !== -1 ? p : p.concat(c);
                  },[]);
}
console.log(destroyer([1, 2, 3, 1, 2, 3], 2, 3));

Answer №2

filter is a built-in function of Arrays in JavaScript. It creates a new array containing elements that pass a specified test. The test function must return a boolean value; if it returns true, the element is included in the new array, and if it returns false, the element is excluded.

For more information, refer to the documentation: Filter- Array

The solution you provided contains a valid test function for filtering out certain elements from the array based on the specified condition (in this case, eliminating certain numbers provided as arguments).

However, there seems to be an issue in your implementation where the test function is not correctly returning true (instead, it is returning undefined, which is a falsy value in JavaScript). As a result, all elements are being filtered out, leading to an empty array being returned.

Note: In JavaScript, true represents all truthy values and false represents all falsy values.

Answer №3

The reason your code isn't functioning correctly is because you are failing to return true.

When using Array.filter, it requires a boolean value to be returned. If true is returned, it will be included in the resulting dataset. If false is returned, it will be skipped.

By not returning anything, it defaults to undefined which is falsey. Therefore, your return array will be empty.

According to MDN,

filter() executes a provided callback for each element in an array, constructing a new array with values for which the callback returns a value that coerces to true.

Answer №4

Take a moment to review the explanation provided by Rajesh on how filter() operates.

It's worth noting that you can achieve the desired outcome without using a separate helper function. Here's a concise version of the code:
Edit: Rajesh's suggestion has led to even further code reduction.

function destroyer(arr) {

  for (var i = 1, filterArr = []; i < arguments.length; i++) {
    filterArr.push(arguments[i]);
  }

  return arguments[0].filter(function(v) {
    return filterArr.indexOf(v)===-1
  });
}

var result = destroyer([1, 2, 3, 1, 2, 5, 3], 2, 3);
console.log(result);

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