Explanation for the strange floating math in JavaScript - Understanding the IEEE 754 standard for laymen

When it comes to JavaScript and working with floating point numbers, I always feel a bit lost. Dealing with decimals makes me nervous because I'm never quite sure what's happening behind the scenes. If only I understood how the IEEE 754 standard operates, then I could anticipate the outcomes more accurately. This predictability would boost my confidence and eliminate my fear.

Can someone please give me a straightforward explanation (similar to explaining binary representations of integers) about the workings of the IEEE 754 standard? How does it lead to situations like 0.1 + 0.2 != 0.3?

Many thanks! :)

Answer №1

Decimal fractions, such as 0.1, present challenges in base 2 representation

Imagine trying to represent the decimal number 0.1 in binary form. This value is equivalent to 1/10. However, when divided by 10 in base-2, the result becomes 0.000110011001100..., displaying a repeating pattern of decimals.

In base-10, accurately expressing numbers like 0.1 is straightforward, but in base-2, exact representation of fractional values based on tenths is impossible. Instead, approximations are required using the available storage capacity for bits.

For instance, if only the first 8 significant binary digits were stored for 0.1, the resulting approximation would be 11001100 (with an exponent of 11). This translates back to 0.000110011 in binary, which computes to 0.099609375 in decimal – not exactly 0.1. This discrepancy signifies the error introduced when converting 0.1 to a floating-point variable with a base of 8 bits, excluding the sign bit.

The mechanics behind storing numerical values in floating-point variables

The IEEE 754 standard outlines a methodology for encoding real numbers into binary format, incorporating a sign and a binary exponent. The application of the exponent occurs within the binary realm, post conversion from decimal to binary.

Varying sizes of IEEE floating-point numbers dictate the allocation of binary digits for the base number and the exponent respectively.

The mismatch seen in computations like 0.1 + 0.2 != 0.3 stems from operating on approximations of these numbers in binary form rather than their precise decimal equivalents. Upon reconverting the outcomes to decimal form, they deviate from the intended values due to this inherent imprecision. Moreover, the resultant sum does not align perfectly with the binary representation of 0.3 either, with the degree of deviation contingent on the precision level set by the floating-point size.

Rounding: a potential remedy, though ineffective in certain scenarios

In circumstances where computational inaccuracies arise from precision loss in binary conversions, rounding can address minor discrepancies during the return transition to decimal notation, fully concealing any errors.

Within the context of 0.1 + 0.2 compared to 0.3, however, rounding fails to rectify the disparity. The addition of the binary estimates of 0.1 and 0.2 results in a figure distinct from the binary approximation of 0.3.

Answer №2

The reason why 1/3 + 1/3 + 1/3 does not equal 1 when converted to 0.333 (or any finite number of 3's) is similar to how 0.333 + 0.333 + 0.333 equals 0.999, not 1.

In a different base, such as base 9, 1/3 can be represented exactly as 0.39, and 0.39 + 0.39 + 0.39 equals 1.09. Some numbers that are exact in one base may need to be rounded in another base for accuracy.

Similarly, certain numbers cannot be represented precisely in base 2 but can in base 10, like 0.2.
0.210 translates to 0.0011001100110011...2
If rounded to 0.00112, the sum will be 0.11112, not 1.00002. (0.11112 is equivalent to 15/16)

This discrepancy affects computers since they perform arithmetic in binary.

Improving accuracy involves using more digits. For instance, 0.3333333310 + 0.3333333310 + 0.3333333310 results in 0.9999999910, closer to the correct answer than 0.99910. A double can store around 15 decimal digits, leading to a relative error of about 10-15 (more precisely, 2-52).

The small margin of error typically doesn't impact outcomes unless:

  • Your program demands high precision,
  • You display with many decimal places (which could show slight deviations like 0.99999999999999995622), or
  • You compare two numbers for equality (== or !=).

Avoid comparing non-integer numbers for equality, but feel free to use them in calculations and comparisons (< or >) without issues (unless extreme precision is necessary).

Answer №3

When working with JavaScript, my usual approach is to utilize a comparison operation such as (Math.abs(.1 + .2 - .3) < .000001).

This coding practice often reminds me of a scenario where adding two separate slices of pizza (.25 each) does not necessarily equal half a pizza (.5), as you lose some pizza when you cut it! It's a fun way to think about mathematical operations in programming.

Answer №4

Understanding the precision of floats is key to gaining confidence in using them. It's important to note that they are typically accurate up to 15 significant digits, which is usually more than enough for everyday tasks.

The specific number of significant digits needed can vary depending on the field you work in - engineers may only require 3, economists may need 5, while scientists might need more (or less). So, it's essential to determine the exact number of significant digits you require before performing any calculations. For example, do you need a precise number like $2,345,876,234 or is an approximation like $2.3 billion acceptable? If your desired precision is around 5 significant digits, you can confidently perform arithmetic with at least 7 significant digits and then round off the final result accordingly.

For instance, if you only need 3 significant digits:

(0.1 + 0.2).toFixed(3) // 0.300

By consistently working with at least two extra significant digits and rounding off to the required precision at the end, you'll minimize any potential errors caused by JavaScript numbers.

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