Error occurs due to a variable being undefined when passed to a callback function within a

Question about Passing Value to JavaScript Callback Functions:
Variable in JavaScript callback functions always gets last value in loop?

I'm having trouble passing the value of 'k' to the callback function within the fadeOut method. Here is my loop code snippet:

 for(var k=0; k<image1.length; k++)
 {

    $(img[k]).fadeOut(200, function(k) {
        alert(k);
        $(this).attr('src', image2[k]);
        $(this).fadeIn(200);
    });
 }

Answer №1

The jQuery fadeOut method requires a callback function without any parameters. According to the official jQuery documentation, "The callback function does not receive any arguments". If you need to access the value of k, consider using the following approach:

for(var k=0;k<image1.length;k++) {
    (function(k) {
        $(img[k]).fadeOut(200,function() {
            alert(k);
            $(this).attr('src', image2[k]);
            $(this).fadeIn(200);
        });
    })(k);
}

Answer №2

To enable the callback to access your variable, you can implement a similar approach like this:

for (var index = 0; index < images.length; index++) {
    (function(index) {
        $(images[index]).fadeOut(300, function() {
            console.log(index);
            this.src = updatedImages[index];
            $(this).fadeIn(300);
        });
    })(index);
}

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