Seeking a more efficient approach to perform this function, could you provide some assistance?
function removeAccents(text) {
var text = text.replace(/á/g, "a").replace(/é/g, "e").replace(/í/g, "i").replace(/ó/g, "o").replace(/ú/g, "u");
return cadenaTexto;
}
Your code seems clean already, perhaps putting the replaces on separate lines could enhance readability, but overall it's easy to comprehend.
I've taken a different approach with the code below, leveraging the ability to use a replacerFunction in String.prototype.replace
This method allows you to define which characters you want to replace along with their replacements in a separate object and simply pass them into the function.
function removeAccents(text) {
const translations = { á: "a", é: "e", í: "i", ó: "o", ú: "u" };
return text.replace(/[áéíóú]/g, match => translations[match]);
}
console.log(removeAccents("áéíóú"));UPDATE: After testing various solutions, @Ryan White's method using the match callback proved to be the most efficient. It showed a significant improvement in performance ranging from 20% for shorter strings to over 100% for longer ones. This approach outperformed the alternatives below as it eliminates the need for loops:
const replacements = { à: 'a', è: 'e', ì: 'i', ò: 'o', ù: 'u' };
function removeAccents3(text) {
const accs = Object.keys(replacements).join('')
return text.replace(
new RegExp(`[${accs}]`, 'gi'),
(match) => replacements[match]
);
}
console.log(removeAccents3('àèbgòè+àòètrysàùì')); //aebgoe+aoetrysaui
// Performance : 69059.40 ops/sI have come up with a few approaches that deliver similar performances. The RegExp replace method stands out as the most efficient, especially with longer strings where it shows a performance boost of over 20%.
const accents = [
{
val: 'à',
repl: 'a',
},
{
val: 'è',
repl: 'e',
},
{
val: 'ì',
repl: 'i',
},
{
val: 'ò',
repl: 'o',
},
{
val: 'ù',
repl: 'u',
},
];
const removeAccents = (text) => {
for (const a of accents) text = text.replace(new RegExp(a.val, 'ig'), a.repl);
return text;
};
console.log("First test:", removeAccents('àèbgòè+àòètrysàùì')); //aebgoe+aoetrysaui
// Performance : 46168.04 ops/s
// 2
const accents2 = {
à: 'a',
è: 'e',
ì: 'i',
ò: 'o',
ù: 'u',
};
const removeAccents2 = (text) => text.split("").map(c => accents2[c] ? accents2[c] : c).join("")
console.log("Second test:", removeAccents2('àèbgòè+àòètrysàùì')); //aebgoe+aoetrysaui
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