I'm struggling to include a variable in an array without it changing. Every time I try to push the variable to the array, it seems to alter.
i = 10;
function addToArray() {
let b = [];
b.push(i);
console.log(b);
}
addToArray();
The variable needs to remain consistent as it represents the total savings in a shopping cart within the application I'm developing.
Understanding the context and scope in JavaScript is crucial.
When creating a function, a new local context and scope are established. Within this scope, an array is defined.
Upon executing the setValue() function, the local context is removed once the execution ends, along with all declared variables.
If you execute setValue() again, a new context with new variables (local scope) is created. This results in the recreation of the array a, which can be changed with each subsequent function call.
To rectify your error, it's important to familiarize yourself with contexts and scopes in JavaScript. You can learn more about this topic here.
Suppose you have a list of values that you want to store in a variable, and these values are stored in an array like this:
const array = [1, 2, 7, 24, 8];
let a = [];//initialize variable a here
You can iterate through the array using a loop to run a function on each value:
for (let i = 0; i < array.length; i++) {
setValue(array[i]);//call a function for each value
}
The function would look like this:
function setValue(val) {
a.push(val);
}
The output will be:
console.log(a);//output: [1, 2, 7, 24, 8]
If you want to add numbers from an input field, you can do it using jQuery:
<input type="number" id="my_input">
Here is the JavaScript code:
let a = [];//Declare a outside onchange function
//Onchange function to capture the new value whenever the input changes
$("#my_input").on("change", function() {
var input = $(this).val();//get new value from the input
setValue(parseFloat(input));//convert to number and call the setValue function
console.log(a);// output
});
The setValue function adds the new value to the array a:
function setValue(val) {
a.push(val);//adds new value to array a
}
See the demo here.
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