Determine the presence of either one or both values in a JavaScript object

Question

Determine the presence of either one or both values in a JavaScript object

I was looking at an Object like this:

{"user": {
    "name": "Harry Peter",
    "phoneNumber": "12345",
    "products": [
        {
            "type": "card",
            "accountId": "5299367",
       },
        {
            "type": "Loan",
            "accountId": "5299365", 
        },
        {
            "type": "card",
            "accountId": "8299388", 
        },
     ]}
}

My question is whether the user has both a loan and a card product, or just a loan.

Are there any existing functions in JavaScript or Angular that can help me find out?

If anyone has suggestions on how to accomplish this, please share. Thank you!

javascript angularjs object

Answer 1

Answer №1

If you're looking to determine whether a user has both a loan and a card, or just a loan as their product, the filter array method could be useful.

var obj = {
    "user": {
    "name": "Harry Peter",
    "phoneNumber": "12345",
    "products": [
        {
            "type": "card",
            "accountId": "5299367",
       },
        {
            "type": "Loan",
            "accountId": "5299365", 
        },
        {
            "type": "card",
            "accountId": "8299388", 
        },
     ]
  }
};
      
var loans = obj.user.products.filter(function(product){
      return product.type === "Loan";
});
      
console.log("Loans: " + loans.length);

if(loans.length === obj.user.products.length){
    console.log("The user has only loans");
}else{
    var cards = obj.user.products.length - loans.length;
    console.log("The user has "+loans.length+" Loan(s) and "+ cards+ " Card(s).");
}

If you want more information on how this method works, feel free to check out this link.

My goal is to determine if the user possesses both a loan and a card, or simply a loan within their product list.

By utilizing the filter method in conjunction with comparing the length of the loans array to the length of all products, you'll be able to address your query effectively.

Answer 2

If you're looking to determine whether a user has both a loan and a card, or just a loan as their product, the filter array method could be useful.

var obj = {
    "user": {
    "name": "Harry Peter",
    "phoneNumber": "12345",
    "products": [
        {
            "type": "card",
            "accountId": "5299367",
       },
        {
            "type": "Loan",
            "accountId": "5299365", 
        },
        {
            "type": "card",
            "accountId": "8299388", 
        },
     ]
  }
};
      
var loans = obj.user.products.filter(function(product){
      return product.type === "Loan";
});
      
console.log("Loans: " + loans.length);

if(loans.length === obj.user.products.length){
    console.log("The user has only loans");
}else{
    var cards = obj.user.products.length - loans.length;
    console.log("The user has "+loans.length+" Loan(s) and "+ cards+ " Card(s).");
}

If you want more information on how this method works, feel free to check out this link.

My goal is to determine if the user possesses both a loan and a card, or simply a loan within their product list.

By utilizing the filter method in conjunction with comparing the length of the loans array to the length of all products, you'll be able to address your query effectively.

Answer 3

Answer №2

You can iterate through the elements in products to extract distinct types

var records = {
  "user": {
    "name": "Harry Peter",
    "phoneNumber": "12345",
    "products": [{
      "type": "card",
      "accountId": "5299367",
    }, {
      "type": "Loan",
      "accountId": "5299365",
    }, {
      "type": "card",
      "accountId": "8299388",
    }, ]
  }
}
                 
var uniqueTypes= records.user.products.reduce(function(previous, current){
  if(previous.indexOf(current.type)<0) previous.push(current.type)
  return previous;                
}, [])
    
console.log(uniqueTypes)

Answer 4

You can iterate through the elements in products to extract distinct types

var records = {
  "user": {
    "name": "Harry Peter",
    "phoneNumber": "12345",
    "products": [{
      "type": "card",
      "accountId": "5299367",
    }, {
      "type": "Loan",
      "accountId": "5299365",
    }, {
      "type": "card",
      "accountId": "8299388",
    }, ]
  }
}
                 
var uniqueTypes= records.user.products.reduce(function(previous, current){
  if(previous.indexOf(current.type)<0) previous.push(current.type)
  return previous;                
}, [])
    
console.log(uniqueTypes)

Answer 5

Answer №3

Feel free to experiment with the following code snippet:

var obj = {
  "user": {
    "name": "Harry Peter",
    "phoneNumber": "12345",
    "products": [{
      "type": "card",
      "accountId": "5299367",
    }, {
      "type": "Loan",
      "accountId": "5299365",
    }, {
      "type": "card",
      "accountId": "8299388",
    }, ]
  }
};

var results = {};

obj.user.products.reduce(function(prevVal, item) {
  prevVal[item.type] = true;
  return prevVal;
}, results);

console.log(results.card && results.Loan); // returns true
// It is worth mentioning that 'results' contains all unique values for types and can be utilized accordingly

Answer 6

Feel free to experiment with the following code snippet:

var obj = {
  "user": {
    "name": "Harry Peter",
    "phoneNumber": "12345",
    "products": [{
      "type": "card",
      "accountId": "5299367",
    }, {
      "type": "Loan",
      "accountId": "5299365",
    }, {
      "type": "card",
      "accountId": "8299388",
    }, ]
  }
};

var results = {};

obj.user.products.reduce(function(prevVal, item) {
  prevVal[item.type] = true;
  return prevVal;
}, results);

console.log(results.card && results.Loan); // returns true
// It is worth mentioning that 'results' contains all unique values for types and can be utilized accordingly

Answer 7

Answer №4

This specific approach offers a Same Iteration solution that accurately determines whether the type is distinct from Loan.

var obj = {"user": {
    "name": "Harry Peter",
    "phoneNumber": "12345",
    "products": [
        {
            "type": "card",
            "accountId": "5299367",
       },
        {
            "type": "Loan",
            "accountId": "5299365", 
        },
        {
            "type": "card",
            "accountId": "8299388", 
        },
     ]}
};
      
function haveDifferentProducts(products){
    var isDiff = false;
    products.forEach(function(product){
       isDiff = product.type != "Loan"; //checks if type not loan
    });
    return isDiff;
}
console.log(haveDifferentProducts(obj.user.products))

Answer 8

This specific approach offers a Same Iteration solution that accurately determines whether the type is distinct from Loan.

var obj = {"user": {
    "name": "Harry Peter",
    "phoneNumber": "12345",
    "products": [
        {
            "type": "card",
            "accountId": "5299367",
       },
        {
            "type": "Loan",
            "accountId": "5299365", 
        },
        {
            "type": "card",
            "accountId": "8299388", 
        },
     ]}
};
      
function haveDifferentProducts(products){
    var isDiff = false;
    products.forEach(function(product){
       isDiff = product.type != "Loan"; //checks if type not loan
    });
    return isDiff;
}
console.log(haveDifferentProducts(obj.user.products))

Answer 9

Answer №5

Utilize the Array filter() method for efficient data filtering.

See it in action with this working demo:

var jsonObj = {
  "user": {
    "name": "Harry Peter",
    "phoneNumber": "12345",
    "products": [
      {
        "type": "card",
        "accountId": "5299367",
      },
      {
        "type": "Loan",
        "accountId": "5299365", 
      },
      {
        "type": "card",
        "accountId": "8299388", 
      },
    ]   
  }
};

var totalLoan = jsonObj.user.products.filter(function(item){
      return item.type == "Loan";
});


var totalCards = jsonObj.user.products.filter(function(item){
      return item.type == "card";
});

if(totalCards.length < 1 && totalLoan.length < 0) {
  console.log("Only loan");
} else if (totalCards.length > 0 && totalLoan.length < 1) {
  console.log("Only card");
} else {
  console.log("Both card as well as loan");
}

Answer 10

Utilize the Array filter() method for efficient data filtering.

See it in action with this working demo:

var jsonObj = {
  "user": {
    "name": "Harry Peter",
    "phoneNumber": "12345",
    "products": [
      {
        "type": "card",
        "accountId": "5299367",
      },
      {
        "type": "Loan",
        "accountId": "5299365", 
      },
      {
        "type": "card",
        "accountId": "8299388", 
      },
    ]   
  }
};

var totalLoan = jsonObj.user.products.filter(function(item){
      return item.type == "Loan";
});


var totalCards = jsonObj.user.products.filter(function(item){
      return item.type == "card";
});

if(totalCards.length < 1 && totalLoan.length < 0) {
  console.log("Only loan");
} else if (totalCards.length > 0 && totalLoan.length < 1) {
  console.log("Only card");
} else {
  console.log("Both card as well as loan");
}

Determine the presence of either one or both values in a JavaScript object

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

Utilize the Array filter() method for efficient data filtering.

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